Metamath Proof Explorer


Theorem k0004ss3

Description: The topological simplex of dimension N is a subset of the base set of Euclidean space of dimension ( N + 1 ) . (Contributed by RP, 29-Mar-2021)

Ref Expression
Hypothesis k0004.a ⊢ 𝐴 = ( 𝑛 ∈ ℕ0 ↦ { 𝑡 ∈ ( ( 0 [,] 1 ) ↑m ( 0 ... 𝑛 ) ) ∣ Σ 𝑘 ∈ ( 0 ... 𝑛 ) ( 𝑡 ‘ 𝑘 ) = 1 } )
Assertion k0004ss3 ( 𝑁 ∈ ℕ0 → ( 𝐴 ‘ 𝑁 ) ⊆ ( Base ‘ ( 𝔼hil ‘ ( 𝑁 + 1 ) ) ) )

Proof

Step Hyp Ref Expression
1 k0004.a ⊢ 𝐴 = ( 𝑛 ∈ ℕ0 ↦ { 𝑡 ∈ ( ( 0 [,] 1 ) ↑m ( 0 ... 𝑛 ) ) ∣ Σ 𝑘 ∈ ( 0 ... 𝑛 ) ( 𝑡 ‘ 𝑘 ) = 1 } )
2 1 k0004ss1 ⊢ ( 𝑁 ∈ ℕ0 → ( 𝐴 ‘ 𝑁 ) ⊆ ( ℝ ↑m ( 0 ... 𝑁 ) ) )
3 nn0z ⊢ ( 𝑁 ∈ ℕ0 → 𝑁 ∈ ℤ )
4 fzval3 ⊢ ( 𝑁 ∈ ℤ → ( 0 ... 𝑁 ) = ( 0 ..^ ( 𝑁 + 1 ) ) )
5 3 4 syl ⊢ ( 𝑁 ∈ ℕ0 → ( 0 ... 𝑁 ) = ( 0 ..^ ( 𝑁 + 1 ) ) )
6 5 oveq2d ⊢ ( 𝑁 ∈ ℕ0 → ( ℝ ↑m ( 0 ... 𝑁 ) ) = ( ℝ ↑m ( 0 ..^ ( 𝑁 + 1 ) ) ) )
7 peano2nn0 ⊢ ( 𝑁 ∈ ℕ0 → ( 𝑁 + 1 ) ∈ ℕ0 )
8 eqid ⊢ ( 𝔼hil ‘ ( 𝑁 + 1 ) ) = ( 𝔼hil ‘ ( 𝑁 + 1 ) )
9 8 ehlbase ⊢ ( ( 𝑁 + 1 ) ∈ ℕ0 → ( ℝ ↑m ( 0 ..^ ( 𝑁 + 1 ) ) ) = ( Base ‘ ( 𝔼hil ‘ ( 𝑁 + 1 ) ) ) )
10 7 9 syl ⊢ ( 𝑁 ∈ ℕ0 → ( ℝ ↑m ( 0 ..^ ( 𝑁 + 1 ) ) ) = ( Base ‘ ( 𝔼hil ‘ ( 𝑁 + 1 ) ) ) )
11 6 10 eqtrd ⊢ ( 𝑁 ∈ ℕ0 → ( ℝ ↑m ( 0 ... 𝑁 ) ) = ( Base ‘ ( 𝔼hil ‘ ( 𝑁 + 1 ) ) ) )
12 2 11 sseqtrd ⊢ ( 𝑁 ∈ ℕ0 → ( 𝐴 ‘ 𝑁 ) ⊆ ( Base ‘ ( 𝔼hil ‘ ( 𝑁 + 1 ) ) ) )