Metamath Proof Explorer


Theorem pi1bas3

Description: The base set of the fundamental group. (Contributed by Mario Carneiro, 10-Jul-2015)

Ref Expression
Hypotheses pi1val.g ⊢ 𝐺 = ( 𝐽 π1 𝑌 )
pi1val.1 ⊢ ( 𝜑 → 𝐽 ∈ ( TopOn ‘ 𝑋 ) )
pi1val.2 ⊢ ( 𝜑 → 𝑌 ∈ 𝑋 )
pi1bas2.b ⊢ ( 𝜑 → 𝐵 = ( Base ‘ 𝐺 ) )
pi1bas3.r ⊢ 𝑅 = ( ( ≃ph ‘ 𝐽 ) ∩ ( ∪ 𝐵 × ∪ 𝐵 ) )
Assertion pi1bas3 ( 𝜑 → 𝐵 = ( ∪ 𝐵 / 𝑅 ) )

Proof

Step Hyp Ref Expression
1 pi1val.g ⊢ 𝐺 = ( 𝐽 π1 𝑌 )
2 pi1val.1 ⊢ ( 𝜑 → 𝐽 ∈ ( TopOn ‘ 𝑋 ) )
3 pi1val.2 ⊢ ( 𝜑 → 𝑌 ∈ 𝑋 )
4 pi1bas2.b ⊢ ( 𝜑 → 𝐵 = ( Base ‘ 𝐺 ) )
5 pi1bas3.r ⊢ 𝑅 = ( ( ≃ph ‘ 𝐽 ) ∩ ( ∪ 𝐵 × ∪ 𝐵 ) )
6 1 2 3 4 pi1bas2 ⊢ ( 𝜑 → 𝐵 = ( ∪ 𝐵 / ( ≃ph ‘ 𝐽 ) ) )
7 eqid ⊢ ( 𝐽 Ω1 𝑌 ) = ( 𝐽 Ω1 𝑌 )
8 eqidd ⊢ ( 𝜑 → ( Base ‘ ( 𝐽 Ω1 𝑌 ) ) = ( Base ‘ ( 𝐽 Ω1 𝑌 ) ) )
9 1 2 3 7 4 8 pi1buni ⊢ ( 𝜑 → ∪ 𝐵 = ( Base ‘ ( 𝐽 Ω1 𝑌 ) ) )
10 1 2 3 7 4 9 pi1blem ⊢ ( 𝜑 → ( ( ( ≃ph ‘ 𝐽 ) “ ∪ 𝐵 ) ⊆ ∪ 𝐵 ∧ ∪ 𝐵 ⊆ ( II Cn 𝐽 ) ) )
11 10 simpld ⊢ ( 𝜑 → ( ( ≃ph ‘ 𝐽 ) “ ∪ 𝐵 ) ⊆ ∪ 𝐵 )
12 qsinxp ⊢ ( ( ( ≃ph ‘ 𝐽 ) “ ∪ 𝐵 ) ⊆ ∪ 𝐵 → ( ∪ 𝐵 / ( ≃ph ‘ 𝐽 ) ) = ( ∪ 𝐵 / ( ( ≃ph ‘ 𝐽 ) ∩ ( ∪ 𝐵 × ∪ 𝐵 ) ) ) )
13 11 12 syl ⊢ ( 𝜑 → ( ∪ 𝐵 / ( ≃ph ‘ 𝐽 ) ) = ( ∪ 𝐵 / ( ( ≃ph ‘ 𝐽 ) ∩ ( ∪ 𝐵 × ∪ 𝐵 ) ) ) )
14 6 13 eqtrd ⊢ ( 𝜑 → 𝐵 = ( ∪ 𝐵 / ( ( ≃ph ‘ 𝐽 ) ∩ ( ∪ 𝐵 × ∪ 𝐵 ) ) ) )
15 qseq2 ⊢ ( 𝑅 = ( ( ≃ph ‘ 𝐽 ) ∩ ( ∪ 𝐵 × ∪ 𝐵 ) ) → ( ∪ 𝐵 / 𝑅 ) = ( ∪ 𝐵 / ( ( ≃ph ‘ 𝐽 ) ∩ ( ∪ 𝐵 × ∪ 𝐵 ) ) ) )
16 5 15 ax-mp ⊢ ( ∪ 𝐵 / 𝑅 ) = ( ∪ 𝐵 / ( ( ≃ph ‘ 𝐽 ) ∩ ( ∪ 𝐵 × ∪ 𝐵 ) ) )
17 14 16 eqtr4di ⊢ ( 𝜑 → 𝐵 = ( ∪ 𝐵 / 𝑅 ) )