Metamath Proof Explorer


Theorem rankeq0b

Description: A set is empty iff its rank is empty. (Contributed by Mario Carneiro, 17-Nov-2014)

Ref Expression
Assertion rankeq0b ( 𝐴 ∈ ∪ ( 𝑅1 “ On ) → ( 𝐴 = ∅ ↔ ( rank ‘ 𝐴 ) = ∅ ) )

Proof

Step Hyp Ref Expression
1 fveq2 ⊢ ( 𝐴 = ∅ → ( rank ‘ 𝐴 ) = ( rank ‘ ∅ ) )
2 r1dmlim ⊢ Lim dom 𝑅1
3 limomss ⊢ ( Lim dom 𝑅1 → ω ⊆ dom 𝑅1 )
4 2 3 ax-mp ⊢ ω ⊆ dom 𝑅1
5 peano1 ⊢ ∅ ∈ ω
6 4 5 sselii ⊢ ∅ ∈ dom 𝑅1
7 rankonid ⊢ ( ∅ ∈ dom 𝑅1 ↔ ( rank ‘ ∅ ) = ∅ )
8 6 7 mpbi ⊢ ( rank ‘ ∅ ) = ∅
9 1 8 eqtrdi ⊢ ( 𝐴 = ∅ → ( rank ‘ 𝐴 ) = ∅ )
10 eqimss ⊢ ( ( rank ‘ 𝐴 ) = ∅ → ( rank ‘ 𝐴 ) ⊆ ∅ )
11 10 adantl ⊢ ( ( 𝐴 ∈ ∪ ( 𝑅1 “ On ) ∧ ( rank ‘ 𝐴 ) = ∅ ) → ( rank ‘ 𝐴 ) ⊆ ∅ )
12 simpl ⊢ ( ( 𝐴 ∈ ∪ ( 𝑅1 “ On ) ∧ ( rank ‘ 𝐴 ) = ∅ ) → 𝐴 ∈ ∪ ( 𝑅1 “ On ) )
13 rankr1bg ⊢ ( ( 𝐴 ∈ ∪ ( 𝑅1 “ On ) ∧ ∅ ∈ dom 𝑅1 ) → ( 𝐴 ⊆ ( 𝑅1 ‘ ∅ ) ↔ ( rank ‘ 𝐴 ) ⊆ ∅ ) )
14 12 6 13 sylancl ⊢ ( ( 𝐴 ∈ ∪ ( 𝑅1 “ On ) ∧ ( rank ‘ 𝐴 ) = ∅ ) → ( 𝐴 ⊆ ( 𝑅1 ‘ ∅ ) ↔ ( rank ‘ 𝐴 ) ⊆ ∅ ) )
15 11 14 mpbird ⊢ ( ( 𝐴 ∈ ∪ ( 𝑅1 “ On ) ∧ ( rank ‘ 𝐴 ) = ∅ ) → 𝐴 ⊆ ( 𝑅1 ‘ ∅ ) )
16 r10 ⊢ ( 𝑅1 ‘ ∅ ) = ∅
17 15 16 sseqtrdi ⊢ ( ( 𝐴 ∈ ∪ ( 𝑅1 “ On ) ∧ ( rank ‘ 𝐴 ) = ∅ ) → 𝐴 ⊆ ∅ )
18 ss0 ⊢ ( 𝐴 ⊆ ∅ → 𝐴 = ∅ )
19 17 18 syl ⊢ ( ( 𝐴 ∈ ∪ ( 𝑅1 “ On ) ∧ ( rank ‘ 𝐴 ) = ∅ ) → 𝐴 = ∅ )
20 19 ex ⊢ ( 𝐴 ∈ ∪ ( 𝑅1 “ On ) → ( ( rank ‘ 𝐴 ) = ∅ → 𝐴 = ∅ ) )
21 9 20 impbid2 ⊢ ( 𝐴 ∈ ∪ ( 𝑅1 “ On ) → ( 𝐴 = ∅ ↔ ( rank ‘ 𝐴 ) = ∅ ) )