Metamath Proof Explorer


Theorem relexpnnrn

Description: The range of an exponentiation of a relation a subset of the relation's field. (Contributed by RP, 23-May-2020)

Ref Expression
Assertion relexpnnrn ( ( 𝑁 ∈ ℕ ∧ 𝑅 ∈ 𝑉 ) → ran ( 𝑅 ↑𝑟 𝑁 ) ⊆ ran 𝑅 )

Proof

Step Hyp Ref Expression
1 cnvexg ⊢ ( 𝑅 ∈ 𝑉 → ◡ 𝑅 ∈ V )
2 relexpnndm ⊢ ( ( 𝑁 ∈ ℕ ∧ ◡ 𝑅 ∈ V ) → dom ( ◡ 𝑅 ↑𝑟 𝑁 ) ⊆ dom ◡ 𝑅 )
3 1 2 sylan2 ⊢ ( ( 𝑁 ∈ ℕ ∧ 𝑅 ∈ 𝑉 ) → dom ( ◡ 𝑅 ↑𝑟 𝑁 ) ⊆ dom ◡ 𝑅 )
4 df-rn ⊢ ran ( 𝑅 ↑𝑟 𝑁 ) = dom ◡ ( 𝑅 ↑𝑟 𝑁 )
5 nnnn0 ⊢ ( 𝑁 ∈ ℕ → 𝑁 ∈ ℕ0 )
6 relexpcnv ⊢ ( ( 𝑁 ∈ ℕ0 ∧ 𝑅 ∈ 𝑉 ) → ◡ ( 𝑅 ↑𝑟 𝑁 ) = ( ◡ 𝑅 ↑𝑟 𝑁 ) )
7 5 6 sylan ⊢ ( ( 𝑁 ∈ ℕ ∧ 𝑅 ∈ 𝑉 ) → ◡ ( 𝑅 ↑𝑟 𝑁 ) = ( ◡ 𝑅 ↑𝑟 𝑁 ) )
8 7 dmeqd ⊢ ( ( 𝑁 ∈ ℕ ∧ 𝑅 ∈ 𝑉 ) → dom ◡ ( 𝑅 ↑𝑟 𝑁 ) = dom ( ◡ 𝑅 ↑𝑟 𝑁 ) )
9 4 8 eqtrid ⊢ ( ( 𝑁 ∈ ℕ ∧ 𝑅 ∈ 𝑉 ) → ran ( 𝑅 ↑𝑟 𝑁 ) = dom ( ◡ 𝑅 ↑𝑟 𝑁 ) )
10 df-rn ⊢ ran 𝑅 = dom ◡ 𝑅
11 10 a1i ⊢ ( ( 𝑁 ∈ ℕ ∧ 𝑅 ∈ 𝑉 ) → ran 𝑅 = dom ◡ 𝑅 )
12 3 9 11 3sstr4d ⊢ ( ( 𝑁 ∈ ℕ ∧ 𝑅 ∈ 𝑉 ) → ran ( 𝑅 ↑𝑟 𝑁 ) ⊆ ran 𝑅 )