Metamath Proof Explorer


Theorem sgrp2nmndlem1

Description: Lemma 1 for sgrp2nmnd : M is a magma, even if A = B ( M is the trivial magma in this case, see mgmb1mgm1 ). (Contributed by AV, 29-Jan-2020)

Ref Expression
Hypotheses mgm2nsgrp.s ⊢ 𝑆 = { 𝐴 , 𝐵 }
mgm2nsgrp.b ⊢ ( Base ‘ 𝑀 ) = 𝑆
sgrp2nmnd.o ⊢ ( +g ‘ 𝑀 ) = ( 𝑥 ∈ 𝑆 , 𝑦 ∈ 𝑆 ↦ if ( 𝑥 = 𝐴 , 𝐴 , 𝐵 ) )
Assertion sgrp2nmndlem1 ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → 𝑀 ∈ Mgm )

Proof

Step Hyp Ref Expression
1 mgm2nsgrp.s ⊢ 𝑆 = { 𝐴 , 𝐵 }
2 mgm2nsgrp.b ⊢ ( Base ‘ 𝑀 ) = 𝑆
3 sgrp2nmnd.o ⊢ ( +g ‘ 𝑀 ) = ( 𝑥 ∈ 𝑆 , 𝑦 ∈ 𝑆 ↦ if ( 𝑥 = 𝐴 , 𝐴 , 𝐵 ) )
4 prid1g ⊢ ( 𝐴 ∈ 𝑉 → 𝐴 ∈ { 𝐴 , 𝐵 } )
5 4 1 eleqtrrdi ⊢ ( 𝐴 ∈ 𝑉 → 𝐴 ∈ 𝑆 )
6 prid2g ⊢ ( 𝐵 ∈ 𝑊 → 𝐵 ∈ { 𝐴 , 𝐵 } )
7 6 1 eleqtrrdi ⊢ ( 𝐵 ∈ 𝑊 → 𝐵 ∈ 𝑆 )
8 2 eqcomi ⊢ 𝑆 = ( Base ‘ 𝑀 )
9 ne0i ⊢ ( 𝐴 ∈ 𝑆 → 𝑆 ≠ ∅ )
10 9 adantr ⊢ ( ( 𝐴 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ) → 𝑆 ≠ ∅ )
11 simpll ⊢ ( ( ( 𝐴 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ) ∧ ( 𝑥 ∈ 𝑆 ∧ 𝑦 ∈ 𝑆 ) ) → 𝐴 ∈ 𝑆 )
12 simplr ⊢ ( ( ( 𝐴 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ) ∧ ( 𝑥 ∈ 𝑆 ∧ 𝑦 ∈ 𝑆 ) ) → 𝐵 ∈ 𝑆 )
13 8 3 10 11 12 opifismgm ⊢ ( ( 𝐴 ∈ 𝑆 ∧ 𝐵 ∈ 𝑆 ) → 𝑀 ∈ Mgm )
14 5 7 13 syl2an ⊢ ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → 𝑀 ∈ Mgm )