Metamath Proof Explorer


Theorem stm1add3i

Description: Sum of states whose meet is 1. (Contributed by NM, 11-Nov-1999) (New usage is discouraged.)

Ref Expression
Hypotheses stle.1 𝐴C
stle.2 𝐵C
stm1add3.3 𝐶C
Assertion stm1add3i ( 𝑆 ∈ States → ( ( 𝑆 ‘ ( ( 𝐴𝐵 ) ∩ 𝐶 ) ) = 1 → ( ( ( 𝑆𝐴 ) + ( 𝑆𝐵 ) ) + ( 𝑆𝐶 ) ) = 3 ) )

Proof

Step Hyp Ref Expression
1 stle.1 𝐴C
2 stle.2 𝐵C
3 stm1add3.3 𝐶C
4 1 2 chincli ( 𝐴𝐵 ) ∈ C
5 4 3 stm1i ( 𝑆 ∈ States → ( ( 𝑆 ‘ ( ( 𝐴𝐵 ) ∩ 𝐶 ) ) = 1 → ( 𝑆 ‘ ( 𝐴𝐵 ) ) = 1 ) )
6 1 2 stm1addi ( 𝑆 ∈ States → ( ( 𝑆 ‘ ( 𝐴𝐵 ) ) = 1 → ( ( 𝑆𝐴 ) + ( 𝑆𝐵 ) ) = 2 ) )
7 5 6 syld ( 𝑆 ∈ States → ( ( 𝑆 ‘ ( ( 𝐴𝐵 ) ∩ 𝐶 ) ) = 1 → ( ( 𝑆𝐴 ) + ( 𝑆𝐵 ) ) = 2 ) )
8 4 3 stm1ri ( 𝑆 ∈ States → ( ( 𝑆 ‘ ( ( 𝐴𝐵 ) ∩ 𝐶 ) ) = 1 → ( 𝑆𝐶 ) = 1 ) )
9 7 8 jcad ( 𝑆 ∈ States → ( ( 𝑆 ‘ ( ( 𝐴𝐵 ) ∩ 𝐶 ) ) = 1 → ( ( ( 𝑆𝐴 ) + ( 𝑆𝐵 ) ) = 2 ∧ ( 𝑆𝐶 ) = 1 ) ) )
10 oveq12 ( ( ( ( 𝑆𝐴 ) + ( 𝑆𝐵 ) ) = 2 ∧ ( 𝑆𝐶 ) = 1 ) → ( ( ( 𝑆𝐴 ) + ( 𝑆𝐵 ) ) + ( 𝑆𝐶 ) ) = ( 2 + 1 ) )
11 df-3 3 = ( 2 + 1 )
12 10 11 eqtr4di ( ( ( ( 𝑆𝐴 ) + ( 𝑆𝐵 ) ) = 2 ∧ ( 𝑆𝐶 ) = 1 ) → ( ( ( 𝑆𝐴 ) + ( 𝑆𝐵 ) ) + ( 𝑆𝐶 ) ) = 3 )
13 9 12 syl6 ( 𝑆 ∈ States → ( ( 𝑆 ‘ ( ( 𝐴𝐵 ) ∩ 𝐶 ) ) = 1 → ( ( ( 𝑆𝐴 ) + ( 𝑆𝐵 ) ) + ( 𝑆𝐶 ) ) = 3 ) )