Metamath Proof Explorer


Theorem trclfvcotrg

Description: The value of the transitive closure of a relation is always a transitive relation. (Contributed by RP, 8-May-2020)

Ref Expression
Assertion trclfvcotrg ( ( t+ ‘ 𝑅 ) ∘ ( t+ ‘ 𝑅 ) ) ⊆ ( t+ ‘ 𝑅 )

Proof

Step Hyp Ref Expression
1 trclfvcotr ⊢ ( 𝑅 ∈ V → ( ( t+ ‘ 𝑅 ) ∘ ( t+ ‘ 𝑅 ) ) ⊆ ( t+ ‘ 𝑅 ) )
2 fvprc ⊢ ( ¬ 𝑅 ∈ V → ( t+ ‘ 𝑅 ) = ∅ )
3 0trrel ⊢ ( ∅ ∘ ∅ ) ⊆ ∅
4 3 a1i ⊢ ( ( t+ ‘ 𝑅 ) = ∅ → ( ∅ ∘ ∅ ) ⊆ ∅ )
5 id ⊢ ( ( t+ ‘ 𝑅 ) = ∅ → ( t+ ‘ 𝑅 ) = ∅ )
6 5 5 coeq12d ⊢ ( ( t+ ‘ 𝑅 ) = ∅ → ( ( t+ ‘ 𝑅 ) ∘ ( t+ ‘ 𝑅 ) ) = ( ∅ ∘ ∅ ) )
7 4 6 5 3sstr4d ⊢ ( ( t+ ‘ 𝑅 ) = ∅ → ( ( t+ ‘ 𝑅 ) ∘ ( t+ ‘ 𝑅 ) ) ⊆ ( t+ ‘ 𝑅 ) )
8 2 7 syl ⊢ ( ¬ 𝑅 ∈ V → ( ( t+ ‘ 𝑅 ) ∘ ( t+ ‘ 𝑅 ) ) ⊆ ( t+ ‘ 𝑅 ) )
9 1 8 pm2.61i ⊢ ( ( t+ ‘ 𝑅 ) ∘ ( t+ ‘ 𝑅 ) ) ⊆ ( t+ ‘ 𝑅 )