Metamath Proof Explorer


Theorem zsbday

Description: A surreal integer has a finite birthday. (Contributed by Scott Fenton, 26-May-2025)

Ref Expression
Assertion zsbday ( 𝐴 ∈ ℤs → ( bday ‘ 𝐴 ) ∈ ω )

Proof

Step Hyp Ref Expression
1 elzn0s ⊢ ( 𝐴 ∈ ℤs ↔ ( 𝐴 ∈ No ∧ ( 𝐴 ∈ ℕ0s ∨ ( -us ‘ 𝐴 ) ∈ ℕ0s ) ) )
2 n0bday ⊢ ( 𝐴 ∈ ℕ0s → ( bday ‘ 𝐴 ) ∈ ω )
3 2 adantl ⊢ ( ( 𝐴 ∈ No ∧ 𝐴 ∈ ℕ0s ) → ( bday ‘ 𝐴 ) ∈ ω )
4 negbday ⊢ ( 𝐴 ∈ No → ( bday ‘ ( -us ‘ 𝐴 ) ) = ( bday ‘ 𝐴 ) )
5 4 adantr ⊢ ( ( 𝐴 ∈ No ∧ ( -us ‘ 𝐴 ) ∈ ℕ0s ) → ( bday ‘ ( -us ‘ 𝐴 ) ) = ( bday ‘ 𝐴 ) )
6 n0bday ⊢ ( ( -us ‘ 𝐴 ) ∈ ℕ0s → ( bday ‘ ( -us ‘ 𝐴 ) ) ∈ ω )
7 6 adantl ⊢ ( ( 𝐴 ∈ No ∧ ( -us ‘ 𝐴 ) ∈ ℕ0s ) → ( bday ‘ ( -us ‘ 𝐴 ) ) ∈ ω )
8 5 7 eqeltrrd ⊢ ( ( 𝐴 ∈ No ∧ ( -us ‘ 𝐴 ) ∈ ℕ0s ) → ( bday ‘ 𝐴 ) ∈ ω )
9 3 8 jaodan ⊢ ( ( 𝐴 ∈ No ∧ ( 𝐴 ∈ ℕ0s ∨ ( -us ‘ 𝐴 ) ∈ ℕ0s ) ) → ( bday ‘ 𝐴 ) ∈ ω )
10 1 9 sylbi ⊢ ( 𝐴 ∈ ℤs → ( bday ‘ 𝐴 ) ∈ ω )