Metamath Proof Explorer


Theorem functermclem

Description: Lemma for functermc . (Contributed by Zhi Wang, 17-Oct-2025)

Ref Expression
Hypotheses functermclem.1
|- ( ( ph /\ K R L ) -> K = F )
functermclem.2
|- ( ph -> ( F R L <-> L = G ) )
Assertion functermclem
|- ( ph -> ( K R L <-> ( K = F /\ L = G ) ) )

Proof

Step Hyp Ref Expression
1 functermclem.1
 |-  ( ( ph /\ K R L ) -> K = F )
2 functermclem.2
 |-  ( ph -> ( F R L <-> L = G ) )
3 simpr
 |-  ( ( ph /\ K R L ) -> K R L )
4 1 3 eqbrtrrd
 |-  ( ( ph /\ K R L ) -> F R L )
5 2 biimpa
 |-  ( ( ph /\ F R L ) -> L = G )
6 4 5 syldan
 |-  ( ( ph /\ K R L ) -> L = G )
7 1 6 jca
 |-  ( ( ph /\ K R L ) -> ( K = F /\ L = G ) )
8 simprl
 |-  ( ( ph /\ ( K = F /\ L = G ) ) -> K = F )
9 2 biimpar
 |-  ( ( ph /\ L = G ) -> F R L )
10 9 adantrl
 |-  ( ( ph /\ ( K = F /\ L = G ) ) -> F R L )
11 8 10 eqbrtrd
 |-  ( ( ph /\ ( K = F /\ L = G ) ) -> K R L )
12 7 11 impbida
 |-  ( ph -> ( K R L <-> ( K = F /\ L = G ) ) )