Metamath Proof Explorer


Theorem 2503lem3

Description: Lemma for 2503prm . Calculate the GCD of 2 ^ 1 8 - 1 == 1 8 3 1 with N = 2 5 0 3 . (Contributed by Mario Carneiro, 3-Mar-2014) (Revised by Mario Carneiro, 20-Apr-2015) (Proof shortened by AV, 15-Sep-2021)

Ref Expression
Hypothesis 2503prm.1 ⊢ N = 2503
Assertion 2503lem3 ⊢ 2 18 − 1 gcd N = 1

Proof

Step Hyp Ref Expression
1 2503prm.1 ⊢ N = 2503
2 2nn ⊢ 2 ∈ ℕ
3 1nn0 ⊢ 1 ∈ ℕ 0
4 8nn0 ⊢ 8 ∈ ℕ 0
5 3 4 deccl ⊢ 18 ∈ ℕ 0
6 nnexpcl ⊢ 2 ∈ ℕ ∧ 18 ∈ ℕ 0 → 2 18 ∈ ℕ
7 2 5 6 mp2an ⊢ 2 18 ∈ ℕ
8 nnm1nn0 ⊢ 2 18 ∈ ℕ → 2 18 − 1 ∈ ℕ 0
9 7 8 ax-mp ⊢ 2 18 − 1 ∈ ℕ 0
10 3nn0 ⊢ 3 ∈ ℕ 0
11 5 10 deccl ⊢ 183 ∈ ℕ 0
12 11 3 deccl ⊢ 1831 ∈ ℕ 0
13 2nn0 ⊢ 2 ∈ ℕ 0
14 5nn0 ⊢ 5 ∈ ℕ 0
15 13 14 deccl ⊢ 25 ∈ ℕ 0
16 0nn0 ⊢ 0 ∈ ℕ 0
17 15 16 deccl ⊢ 250 ∈ ℕ 0
18 3nn ⊢ 3 ∈ ℕ
19 17 18 decnncl ⊢ 2503 ∈ ℕ
20 1 19 eqeltri ⊢ N ∈ ℕ
21 1 2503lem1 ⊢ 2 18 mod N = 1832 mod N
22 1p1e2 ⊢ 1 + 1 = 2
23 eqid ⊢ 1831 = 1831
24 11 3 22 23 decsuc ⊢ 1831 + 1 = 1832
25 20 7 3 12 21 24 modsubi ⊢ 2 18 − 1 mod N = 1831 mod N
26 6nn0 ⊢ 6 ∈ ℕ 0
27 7nn0 ⊢ 7 ∈ ℕ 0
28 26 27 deccl ⊢ 67 ∈ ℕ 0
29 28 13 deccl ⊢ 672 ∈ ℕ 0
30 4nn0 ⊢ 4 ∈ ℕ 0
31 30 4 deccl ⊢ 48 ∈ ℕ 0
32 31 27 deccl ⊢ 487 ∈ ℕ 0
33 5 14 deccl ⊢ 185 ∈ ℕ 0
34 3 3 deccl ⊢ 11 ∈ ℕ 0
35 34 27 deccl ⊢ 117 ∈ ℕ 0
36 26 4 deccl ⊢ 68 ∈ ℕ 0
37 9nn0 ⊢ 9 ∈ ℕ 0
38 30 37 deccl ⊢ 49 ∈ ℕ 0
39 3 37 deccl ⊢ 19 ∈ ℕ 0
40 38 nn0zi ⊢ 49 ∈ ℤ
41 39 nn0zi ⊢ 19 ∈ ℤ
42 gcdcom ⊢ 49 ∈ ℤ ∧ 19 ∈ ℤ → 49 gcd 19 = 19 gcd 49
43 40 41 42 mp2an ⊢ 49 gcd 19 = 19 gcd 49
44 9nn ⊢ 9 ∈ ℕ
45 3 44 decnncl ⊢ 19 ∈ ℕ
46 1nn ⊢ 1 ∈ ℕ
47 3 46 decnncl ⊢ 11 ∈ ℕ
48 eqid ⊢ 19 = 19
49 eqid ⊢ 11 = 11
50 2cn ⊢ 2 ∈ ℂ
51 50 mullidi ⊢ 1 ⋅ 2 = 2
52 51 22 oveq12i ⊢ 1 ⋅ 2 + 1 + 1 = 2 + 2
53 2p2e4 ⊢ 2 + 2 = 4
54 52 53 eqtri ⊢ 1 ⋅ 2 + 1 + 1 = 4
55 8p1e9 ⊢ 8 + 1 = 9
56 9t2e18 ⊢ 9 ⋅ 2 = 18
57 3 4 55 56 decsuc ⊢ 9 ⋅ 2 + 1 = 19
58 3 37 3 3 48 49 13 37 3 54 57 decmac ⊢ 19 ⋅ 2 + 11 = 49
59 1lt9 ⊢ 1 < 9
60 3 3 44 59 declt ⊢ 11 < 19
61 45 13 47 58 60 ndvdsi ⊢ ¬ 19 ∥ 49
62 19prm ⊢ 19 ∈ ℙ
63 coprm ⊢ 19 ∈ ℙ ∧ 49 ∈ ℤ → ¬ 19 ∥ 49 ↔ 19 gcd 49 = 1
64 62 40 63 mp2an ⊢ ¬ 19 ∥ 49 ↔ 19 gcd 49 = 1
65 61 64 mpbi ⊢ 19 gcd 49 = 1
66 43 65 eqtri ⊢ 49 gcd 19 = 1
67 eqid ⊢ 49 = 49
68 4cn ⊢ 4 ∈ ℂ
69 68 mullidi ⊢ 1 ⋅ 4 = 4
70 69 22 oveq12i ⊢ 1 ⋅ 4 + 1 + 1 = 4 + 2
71 4p2e6 ⊢ 4 + 2 = 6
72 70 71 eqtri ⊢ 1 ⋅ 4 + 1 + 1 = 6
73 9cn ⊢ 9 ∈ ℂ
74 73 mullidi ⊢ 1 ⋅ 9 = 9
75 74 oveq1i ⊢ 1 ⋅ 9 + 9 = 9 + 9
76 9p9e18 ⊢ 9 + 9 = 18
77 75 76 eqtri ⊢ 1 ⋅ 9 + 9 = 18
78 30 37 3 37 67 48 3 4 3 72 77 decma2c ⊢ 1 ⋅ 49 + 19 = 68
79 3 39 38 66 78 gcdi ⊢ 68 gcd 49 = 1
80 eqid ⊢ 68 = 68
81 6cn ⊢ 6 ∈ ℂ
82 81 mullidi ⊢ 1 ⋅ 6 = 6
83 4p1e5 ⊢ 4 + 1 = 5
84 82 83 oveq12i ⊢ 1 ⋅ 6 + 4 + 1 = 6 + 5
85 6p5e11 ⊢ 6 + 5 = 11
86 84 85 eqtri ⊢ 1 ⋅ 6 + 4 + 1 = 11
87 8cn ⊢ 8 ∈ ℂ
88 87 mullidi ⊢ 1 ⋅ 8 = 8
89 88 oveq1i ⊢ 1 ⋅ 8 + 9 = 8 + 9
90 9p8e17 ⊢ 9 + 8 = 17
91 73 87 90 addcomli ⊢ 8 + 9 = 17
92 89 91 eqtri ⊢ 1 ⋅ 8 + 9 = 17
93 26 4 30 37 80 67 3 27 3 86 92 decma2c ⊢ 1 ⋅ 68 + 49 = 117
94 3 38 36 79 93 gcdi ⊢ 117 gcd 68 = 1
95 eqid ⊢ 117 = 117
96 6p1e7 ⊢ 6 + 1 = 7
97 27 dec0h ⊢ 7 = 07
98 96 97 eqtri ⊢ 6 + 1 = 07
99 1t1e1 ⊢ 1 ⋅ 1 = 1
100 00id ⊢ 0 + 0 = 0
101 99 100 oveq12i ⊢ 1 ⋅ 1 + 0 + 0 = 1 + 0
102 ax-1cn ⊢ 1 ∈ ℂ
103 102 addridi ⊢ 1 + 0 = 1
104 101 103 eqtri ⊢ 1 ⋅ 1 + 0 + 0 = 1
105 99 oveq1i ⊢ 1 ⋅ 1 + 7 = 1 + 7
106 7cn ⊢ 7 ∈ ℂ
107 7p1e8 ⊢ 7 + 1 = 8
108 106 102 107 addcomli ⊢ 1 + 7 = 8
109 4 dec0h ⊢ 8 = 08
110 105 108 109 3eqtri ⊢ 1 ⋅ 1 + 7 = 08
111 3 3 16 27 49 98 3 4 16 104 110 decma2c ⊢ 1 ⋅ 11 + 6 + 1 = 18
112 106 mullidi ⊢ 1 ⋅ 7 = 7
113 112 oveq1i ⊢ 1 ⋅ 7 + 8 = 7 + 8
114 8p7e15 ⊢ 8 + 7 = 15
115 87 106 114 addcomli ⊢ 7 + 8 = 15
116 113 115 eqtri ⊢ 1 ⋅ 7 + 8 = 15
117 34 27 26 4 95 80 3 14 3 111 116 decma2c ⊢ 1 ⋅ 117 + 68 = 185
118 3 36 35 94 117 gcdi ⊢ 185 gcd 117 = 1
119 eqid ⊢ 185 = 185
120 eqid ⊢ 18 = 18
121 3 3 22 49 decsuc ⊢ 11 + 1 = 12
122 2t1e2 ⊢ 2 ⋅ 1 = 2
123 122 22 oveq12i ⊢ 2 ⋅ 1 + 1 + 1 = 2 + 2
124 123 53 eqtri ⊢ 2 ⋅ 1 + 1 + 1 = 4
125 8t2e16 ⊢ 8 ⋅ 2 = 16
126 87 50 125 mulcomli ⊢ 2 ⋅ 8 = 16
127 6p2e8 ⊢ 6 + 2 = 8
128 3 26 13 126 127 decaddi ⊢ 2 ⋅ 8 + 2 = 18
129 3 4 3 13 120 121 13 4 3 124 128 decma2c ⊢ 2 ⋅ 18 + 11 + 1 = 48
130 5cn ⊢ 5 ∈ ℂ
131 5t2e10 ⊢ 5 ⋅ 2 = 10
132 130 50 131 mulcomli ⊢ 2 ⋅ 5 = 10
133 106 addlidi ⊢ 0 + 7 = 7
134 3 16 27 132 133 decaddi ⊢ 2 ⋅ 5 + 7 = 17
135 5 14 34 27 119 95 13 27 3 129 134 decma2c ⊢ 2 ⋅ 185 + 117 = 487
136 13 35 33 118 135 gcdi ⊢ 487 gcd 185 = 1
137 eqid ⊢ 487 = 487
138 eqid ⊢ 48 = 48
139 3 4 55 120 decsuc ⊢ 18 + 1 = 19
140 30 4 3 37 138 139 3 27 3 72 92 decma2c ⊢ 1 ⋅ 48 + 18 + 1 = 67
141 112 oveq1i ⊢ 1 ⋅ 7 + 5 = 7 + 5
142 7p5e12 ⊢ 7 + 5 = 12
143 141 142 eqtri ⊢ 1 ⋅ 7 + 5 = 12
144 31 27 5 14 137 119 3 13 3 140 143 decma2c ⊢ 1 ⋅ 487 + 185 = 672
145 3 33 32 136 144 gcdi ⊢ 672 gcd 487 = 1
146 eqid ⊢ 672 = 672
147 eqid ⊢ 67 = 67
148 30 4 55 138 decsuc ⊢ 48 + 1 = 49
149 71 oveq2i ⊢ 2 ⋅ 6 + 4 + 2 = 2 ⋅ 6 + 6
150 6t2e12 ⊢ 6 ⋅ 2 = 12
151 81 50 150 mulcomli ⊢ 2 ⋅ 6 = 12
152 81 50 127 addcomli ⊢ 2 + 6 = 8
153 3 13 26 151 152 decaddi ⊢ 2 ⋅ 6 + 6 = 18
154 149 153 eqtri ⊢ 2 ⋅ 6 + 4 + 2 = 18
155 7t2e14 ⊢ 7 ⋅ 2 = 14
156 106 50 155 mulcomli ⊢ 2 ⋅ 7 = 14
157 9p4e13 ⊢ 9 + 4 = 13
158 73 68 157 addcomli ⊢ 4 + 9 = 13
159 3 30 37 156 22 10 158 decaddci ⊢ 2 ⋅ 7 + 9 = 23
160 26 27 30 37 147 148 13 10 13 154 159 decma2c ⊢ 2 ⋅ 67 + 48 + 1 = 183
161 2t2e4 ⊢ 2 ⋅ 2 = 4
162 161 oveq1i ⊢ 2 ⋅ 2 + 7 = 4 + 7
163 7p4e11 ⊢ 7 + 4 = 11
164 106 68 163 addcomli ⊢ 4 + 7 = 11
165 162 164 eqtri ⊢ 2 ⋅ 2 + 7 = 11
166 28 13 31 27 146 137 13 3 3 160 165 decma2c ⊢ 2 ⋅ 672 + 487 = 1831
167 13 32 29 145 166 gcdi ⊢ 1831 gcd 672 = 1
168 eqid ⊢ 183 = 183
169 28 nn0cni ⊢ 67 ∈ ℂ
170 169 addridi ⊢ 67 + 0 = 67
171 102 addlidi ⊢ 0 + 1 = 1
172 99 171 oveq12i ⊢ 1 ⋅ 1 + 0 + 1 = 1 + 1
173 172 22 eqtri ⊢ 1 ⋅ 1 + 0 + 1 = 2
174 88 oveq1i ⊢ 1 ⋅ 8 + 7 = 8 + 7
175 174 114 eqtri ⊢ 1 ⋅ 8 + 7 = 15
176 3 4 16 27 120 98 3 14 3 173 175 decma2c ⊢ 1 ⋅ 18 + 6 + 1 = 25
177 3cn ⊢ 3 ∈ ℂ
178 177 mullidi ⊢ 1 ⋅ 3 = 3
179 178 oveq1i ⊢ 1 ⋅ 3 + 7 = 3 + 7
180 7p3e10 ⊢ 7 + 3 = 10
181 106 177 180 addcomli ⊢ 3 + 7 = 10
182 179 181 eqtri ⊢ 1 ⋅ 3 + 7 = 10
183 5 10 26 27 168 170 3 16 3 176 182 decma2c ⊢ 1 ⋅ 183 + 67 + 0 = 250
184 99 oveq1i ⊢ 1 ⋅ 1 + 2 = 1 + 2
185 1p2e3 ⊢ 1 + 2 = 3
186 10 dec0h ⊢ 3 = 03
187 184 185 186 3eqtri ⊢ 1 ⋅ 1 + 2 = 03
188 11 3 28 13 23 146 3 10 16 183 187 decma2c ⊢ 1 ⋅ 1831 + 672 = 2503
189 188 1 eqtr4i ⊢ 1 ⋅ 1831 + 672 = N
190 3 29 12 167 189 gcdi ⊢ N gcd 1831 = 1
191 9 12 20 25 190 gcdmodi ⊢ 2 18 − 1 gcd N = 1