Metamath Proof Explorer


Theorem ablsimpgfindlem2

Description: Lemma for ablsimpgfind . An element of an abelian finite simple group which squares to the identity has finite order. (Contributed by Rohan Ridenour, 3-Aug-2023)

Ref Expression
Hypotheses ablsimpgfindlem1.1 ⊢ B = Base G
ablsimpgfindlem1.2 ⊢ 0 ˙ = 0 G
ablsimpgfindlem1.3 ⊢ · ˙ = ⋅ G
ablsimpgfindlem1.4 ⊢ O = od ⁡ G
ablsimpgfindlem1.5 ⊢ φ → G ∈ Abel
ablsimpgfindlem1.6 ⊢ φ → G ∈ SimpGrp
Assertion ablsimpgfindlem2 ⊢ φ ∧ x ∈ B ∧ 2 · ˙ x = 0 ˙ → O ⁡ x ≠ 0

Proof

Step Hyp Ref Expression
1 ablsimpgfindlem1.1 ⊢ B = Base G
2 ablsimpgfindlem1.2 ⊢ 0 ˙ = 0 G
3 ablsimpgfindlem1.3 ⊢ · ˙ = ⋅ G
4 ablsimpgfindlem1.4 ⊢ O = od ⁡ G
5 ablsimpgfindlem1.5 ⊢ φ → G ∈ Abel
6 ablsimpgfindlem1.6 ⊢ φ → G ∈ SimpGrp
7 simpr ⊢ φ ∧ x ∈ B ∧ 2 · ˙ x = 0 ˙ → 2 · ˙ x = 0 ˙
8 6 simpggrpd ⊢ φ → G ∈ Grp
9 8 adantr ⊢ φ ∧ x ∈ B → G ∈ Grp
10 simpr ⊢ φ ∧ x ∈ B → x ∈ B
11 2z ⊢ 2 ∈ ℤ
12 11 a1i ⊢ φ ∧ x ∈ B → 2 ∈ ℤ
13 9 10 12 3jca ⊢ φ ∧ x ∈ B → G ∈ Grp ∧ x ∈ B ∧ 2 ∈ ℤ
14 13 adantr ⊢ φ ∧ x ∈ B ∧ 2 · ˙ x = 0 ˙ → G ∈ Grp ∧ x ∈ B ∧ 2 ∈ ℤ
15 1 4 3 2 oddvds ⊢ G ∈ Grp ∧ x ∈ B ∧ 2 ∈ ℤ → O ⁡ x ∥ 2 ↔ 2 · ˙ x = 0 ˙
16 14 15 syl ⊢ φ ∧ x ∈ B ∧ 2 · ˙ x = 0 ˙ → O ⁡ x ∥ 2 ↔ 2 · ˙ x = 0 ˙
17 7 16 mpbird ⊢ φ ∧ x ∈ B ∧ 2 · ˙ x = 0 ˙ → O ⁡ x ∥ 2
18 2ne0 ⊢ 2 ≠ 0
19 18 a1i ⊢ φ ∧ x ∈ B ∧ 2 · ˙ x = 0 ˙ → 2 ≠ 0
20 19 neneqd ⊢ φ ∧ x ∈ B ∧ 2 · ˙ x = 0 ˙ → ¬ 2 = 0
21 0dvds ⊢ 2 ∈ ℤ → 0 ∥ 2 ↔ 2 = 0
22 11 21 ax-mp ⊢ 0 ∥ 2 ↔ 2 = 0
23 20 22 sylnibr ⊢ φ ∧ x ∈ B ∧ 2 · ˙ x = 0 ˙ → ¬ 0 ∥ 2
24 nbrne2 ⊢ O ⁡ x ∥ 2 ∧ ¬ 0 ∥ 2 → O ⁡ x ≠ 0
25 17 23 24 syl2anc ⊢ φ ∧ x ∈ B ∧ 2 · ˙ x = 0 ˙ → O ⁡ x ≠ 0