Metamath Proof Explorer


Theorem absefib

Description: A complex number is real iff the exponential of its product with _i has absolute value one. (Contributed by NM, 21-Aug-2008)

Ref Expression
Assertion absefib ⊢ A ∈ ℂ → A ∈ ℝ ↔ e i ⁢ A = 1

Proof

Step Hyp Ref Expression
1 ef0 ⊢ e 0 = 1
2 1 eqeq2i ⊢ e − ℑ ⁡ A = e 0 ↔ e − ℑ ⁡ A = 1
3 imcl ⊢ A ∈ ℂ → ℑ ⁡ A ∈ ℝ
4 3 renegcld ⊢ A ∈ ℂ → − ℑ ⁡ A ∈ ℝ
5 0re ⊢ 0 ∈ ℝ
6 reef11 ⊢ − ℑ ⁡ A ∈ ℝ ∧ 0 ∈ ℝ → e − ℑ ⁡ A = e 0 ↔ − ℑ ⁡ A = 0
7 4 5 6 sylancl ⊢ A ∈ ℂ → e − ℑ ⁡ A = e 0 ↔ − ℑ ⁡ A = 0
8 2 7 bitr3id ⊢ A ∈ ℂ → e − ℑ ⁡ A = 1 ↔ − ℑ ⁡ A = 0
9 3 recnd ⊢ A ∈ ℂ → ℑ ⁡ A ∈ ℂ
10 9 negeq0d ⊢ A ∈ ℂ → ℑ ⁡ A = 0 ↔ − ℑ ⁡ A = 0
11 8 10 bitr4d ⊢ A ∈ ℂ → e − ℑ ⁡ A = 1 ↔ ℑ ⁡ A = 0
12 ax-icn ⊢ i ∈ ℂ
13 mulcl ⊢ i ∈ ℂ ∧ A ∈ ℂ → i ⁢ A ∈ ℂ
14 12 13 mpan ⊢ A ∈ ℂ → i ⁢ A ∈ ℂ
15 absef ⊢ i ⁢ A ∈ ℂ → e i ⁢ A = e ℜ ⁡ i ⁢ A
16 14 15 syl ⊢ A ∈ ℂ → e i ⁢ A = e ℜ ⁡ i ⁢ A
17 recl ⊢ A ∈ ℂ → ℜ ⁡ A ∈ ℝ
18 17 recnd ⊢ A ∈ ℂ → ℜ ⁡ A ∈ ℂ
19 mulcl ⊢ i ∈ ℂ ∧ ℑ ⁡ A ∈ ℂ → i ⁢ ℑ ⁡ A ∈ ℂ
20 12 9 19 sylancr ⊢ A ∈ ℂ → i ⁢ ℑ ⁡ A ∈ ℂ
21 replim ⊢ A ∈ ℂ → A = ℜ ⁡ A + i ⁢ ℑ ⁡ A
22 18 20 21 comraddd ⊢ A ∈ ℂ → A = i ⁢ ℑ ⁡ A + ℜ ⁡ A
23 22 oveq2d ⊢ A ∈ ℂ → i ⁢ A = i ⁢ i ⁢ ℑ ⁡ A + ℜ ⁡ A
24 adddi ⊢ i ∈ ℂ ∧ i ⁢ ℑ ⁡ A ∈ ℂ ∧ ℜ ⁡ A ∈ ℂ → i ⁢ i ⁢ ℑ ⁡ A + ℜ ⁡ A = i ⁢ i ⁢ ℑ ⁡ A + i ⁢ ℜ ⁡ A
25 12 20 18 24 mp3an2i ⊢ A ∈ ℂ → i ⁢ i ⁢ ℑ ⁡ A + ℜ ⁡ A = i ⁢ i ⁢ ℑ ⁡ A + i ⁢ ℜ ⁡ A
26 ixi ⊢ i ⁢ i = − 1
27 26 oveq1i ⊢ i ⁢ i ⁢ ℑ ⁡ A = -1 ⁢ ℑ ⁡ A
28 mulass ⊢ i ∈ ℂ ∧ i ∈ ℂ ∧ ℑ ⁡ A ∈ ℂ → i ⁢ i ⁢ ℑ ⁡ A = i ⁢ i ⁢ ℑ ⁡ A
29 12 12 9 28 mp3an12i ⊢ A ∈ ℂ → i ⁢ i ⁢ ℑ ⁡ A = i ⁢ i ⁢ ℑ ⁡ A
30 9 mulm1d ⊢ A ∈ ℂ → -1 ⁢ ℑ ⁡ A = − ℑ ⁡ A
31 27 29 30 3eqtr3a ⊢ A ∈ ℂ → i ⁢ i ⁢ ℑ ⁡ A = − ℑ ⁡ A
32 31 oveq1d ⊢ A ∈ ℂ → i ⁢ i ⁢ ℑ ⁡ A + i ⁢ ℜ ⁡ A = - ℑ ⁡ A + i ⁢ ℜ ⁡ A
33 25 32 eqtrd ⊢ A ∈ ℂ → i ⁢ i ⁢ ℑ ⁡ A + ℜ ⁡ A = - ℑ ⁡ A + i ⁢ ℜ ⁡ A
34 23 33 eqtrd ⊢ A ∈ ℂ → i ⁢ A = - ℑ ⁡ A + i ⁢ ℜ ⁡ A
35 34 fveq2d ⊢ A ∈ ℂ → ℜ ⁡ i ⁢ A = ℜ ⁡ - ℑ ⁡ A + i ⁢ ℜ ⁡ A
36 4 17 crred ⊢ A ∈ ℂ → ℜ ⁡ - ℑ ⁡ A + i ⁢ ℜ ⁡ A = − ℑ ⁡ A
37 35 36 eqtrd ⊢ A ∈ ℂ → ℜ ⁡ i ⁢ A = − ℑ ⁡ A
38 37 fveq2d ⊢ A ∈ ℂ → e ℜ ⁡ i ⁢ A = e − ℑ ⁡ A
39 16 38 eqtrd ⊢ A ∈ ℂ → e i ⁢ A = e − ℑ ⁡ A
40 39 eqeq1d ⊢ A ∈ ℂ → e i ⁢ A = 1 ↔ e − ℑ ⁡ A = 1
41 reim0b ⊢ A ∈ ℂ → A ∈ ℝ ↔ ℑ ⁡ A = 0
42 11 40 41 3bitr4rd ⊢ A ∈ ℂ → A ∈ ℝ ↔ e i ⁢ A = 1