Metamath Proof Explorer


Theorem arwrid

Description: Right identity of a category using arrow notation. (Contributed by Mario Carneiro, 11-Jan-2017)

Ref Expression
Hypotheses arwlid.h ⊢ H = Hom a ⁡ C
arwlid.o ⊢ · ˙ = comp a ⁡ C
arwlid.a ⊢ 1 ˙ = Id a ⁡ C
arwlid.f ⊢ φ → F ∈ X H Y
Assertion arwrid ⊢ φ → F · ˙ 1 ˙ ⁡ X = F

Proof

Step Hyp Ref Expression
1 arwlid.h ⊢ H = Hom a ⁡ C
2 arwlid.o ⊢ · ˙ = comp a ⁡ C
3 arwlid.a ⊢ 1 ˙ = Id a ⁡ C
4 arwlid.f ⊢ φ → F ∈ X H Y
5 eqid ⊢ Base C = Base C
6 1 homarcl ⊢ F ∈ X H Y → C ∈ Cat
7 4 6 syl ⊢ φ → C ∈ Cat
8 eqid ⊢ Id ⁡ C = Id ⁡ C
9 1 5 homarcl2 ⊢ F ∈ X H Y → X ∈ Base C ∧ Y ∈ Base C
10 4 9 syl ⊢ φ → X ∈ Base C ∧ Y ∈ Base C
11 10 simpld ⊢ φ → X ∈ Base C
12 3 5 7 8 11 ida2 ⊢ φ → 2 nd ⁡ 1 ˙ ⁡ X = Id ⁡ C ⁡ X
13 12 oveq2d ⊢ φ → 2 nd ⁡ F X X comp ⁡ C Y 2 nd ⁡ 1 ˙ ⁡ X = 2 nd ⁡ F X X comp ⁡ C Y Id ⁡ C ⁡ X
14 eqid ⊢ Hom ⁡ C = Hom ⁡ C
15 eqid ⊢ comp ⁡ C = comp ⁡ C
16 10 simprd ⊢ φ → Y ∈ Base C
17 1 14 homahom ⊢ F ∈ X H Y → 2 nd ⁡ F ∈ X Hom ⁡ C Y
18 4 17 syl ⊢ φ → 2 nd ⁡ F ∈ X Hom ⁡ C Y
19 5 14 8 7 11 15 16 18 catrid ⊢ φ → 2 nd ⁡ F X X comp ⁡ C Y Id ⁡ C ⁡ X = 2 nd ⁡ F
20 13 19 eqtrd ⊢ φ → 2 nd ⁡ F X X comp ⁡ C Y 2 nd ⁡ 1 ˙ ⁡ X = 2 nd ⁡ F
21 20 oteq3d ⊢ φ → X Y 2 nd ⁡ F X X comp ⁡ C Y 2 nd ⁡ 1 ˙ ⁡ X = X Y 2 nd ⁡ F
22 3 5 7 11 1 idahom ⊢ φ → 1 ˙ ⁡ X ∈ X H X
23 2 1 22 4 15 coaval ⊢ φ → F · ˙ 1 ˙ ⁡ X = X Y 2 nd ⁡ F X X comp ⁡ C Y 2 nd ⁡ 1 ˙ ⁡ X
24 1 homadmcd ⊢ F ∈ X H Y → F = X Y 2 nd ⁡ F
25 4 24 syl ⊢ φ → F = X Y 2 nd ⁡ F
26 21 23 25 3eqtr4d ⊢ φ → F · ˙ 1 ˙ ⁡ X = F