Metamath Proof Explorer


Theorem bcthlem3

Description: Lemma for bcth . The limit point of the centers in the sequence is in the intersection of every ball in the sequence. (Contributed by Mario Carneiro, 7-Jan-2014)

Ref Expression
Hypotheses bcth.2 ⊢ J = MetOpen ⁡ D
bcthlem.4 ⊢ φ → D ∈ CMet ⁡ X
bcthlem.5 ⊢ F = k ∈ ℕ , z ∈ X × ℝ + ⟼ x r | x ∈ X ∧ r ∈ ℝ + ∧ r < 1 k ∧ cls ⁡ J ⁡ x ball ⁡ D r ⊆ ball ⁡ D ⁡ z ∖ M ⁡ k
bcthlem.6 ⊢ φ → M : ℕ ⟶ Clsd ⁡ J
bcthlem.7 ⊢ φ → R ∈ ℝ +
bcthlem.8 ⊢ φ → C ∈ X
bcthlem.9 ⊢ φ → g : ℕ ⟶ X × ℝ +
bcthlem.10 ⊢ φ → g ⁡ 1 = C R
bcthlem.11 ⊢ φ → ∀ k ∈ ℕ g ⁡ k + 1 ∈ k F g ⁡ k
Assertion bcthlem3 ⊢ φ ∧ 1 st ∘ g ⇝t ⁡ J x ∧ A ∈ ℕ → x ∈ ball ⁡ D ⁡ g ⁡ A

Proof

Step Hyp Ref Expression
1 bcth.2 ⊢ J = MetOpen ⁡ D
2 bcthlem.4 ⊢ φ → D ∈ CMet ⁡ X
3 bcthlem.5 ⊢ F = k ∈ ℕ , z ∈ X × ℝ + ⟼ x r | x ∈ X ∧ r ∈ ℝ + ∧ r < 1 k ∧ cls ⁡ J ⁡ x ball ⁡ D r ⊆ ball ⁡ D ⁡ z ∖ M ⁡ k
4 bcthlem.6 ⊢ φ → M : ℕ ⟶ Clsd ⁡ J
5 bcthlem.7 ⊢ φ → R ∈ ℝ +
6 bcthlem.8 ⊢ φ → C ∈ X
7 bcthlem.9 ⊢ φ → g : ℕ ⟶ X × ℝ +
8 bcthlem.10 ⊢ φ → g ⁡ 1 = C R
9 bcthlem.11 ⊢ φ → ∀ k ∈ ℕ g ⁡ k + 1 ∈ k F g ⁡ k
10 fvoveq1 ⊢ k = A → g ⁡ k + 1 = g ⁡ A + 1
11 id ⊢ k = A → k = A
12 fveq2 ⊢ k = A → g ⁡ k = g ⁡ A
13 11 12 oveq12d ⊢ k = A → k F g ⁡ k = A F g ⁡ A
14 10 13 eleq12d ⊢ k = A → g ⁡ k + 1 ∈ k F g ⁡ k ↔ g ⁡ A + 1 ∈ A F g ⁡ A
15 14 rspccva ⊢ ∀ k ∈ ℕ g ⁡ k + 1 ∈ k F g ⁡ k ∧ A ∈ ℕ → g ⁡ A + 1 ∈ A F g ⁡ A
16 9 15 sylan ⊢ φ ∧ A ∈ ℕ → g ⁡ A + 1 ∈ A F g ⁡ A
17 7 ffvelcdmda ⊢ φ ∧ A ∈ ℕ → g ⁡ A ∈ X × ℝ +
18 1 2 3 bcthlem1 ⊢ φ ∧ A ∈ ℕ ∧ g ⁡ A ∈ X × ℝ + → g ⁡ A + 1 ∈ A F g ⁡ A ↔ g ⁡ A + 1 ∈ X × ℝ + ∧ 2 nd ⁡ g ⁡ A + 1 < 1 A ∧ cls ⁡ J ⁡ ball ⁡ D ⁡ g ⁡ A + 1 ⊆ ball ⁡ D ⁡ g ⁡ A ∖ M ⁡ A
19 18 expr ⊢ φ ∧ A ∈ ℕ → g ⁡ A ∈ X × ℝ + → g ⁡ A + 1 ∈ A F g ⁡ A ↔ g ⁡ A + 1 ∈ X × ℝ + ∧ 2 nd ⁡ g ⁡ A + 1 < 1 A ∧ cls ⁡ J ⁡ ball ⁡ D ⁡ g ⁡ A + 1 ⊆ ball ⁡ D ⁡ g ⁡ A ∖ M ⁡ A
20 17 19 mpd ⊢ φ ∧ A ∈ ℕ → g ⁡ A + 1 ∈ A F g ⁡ A ↔ g ⁡ A + 1 ∈ X × ℝ + ∧ 2 nd ⁡ g ⁡ A + 1 < 1 A ∧ cls ⁡ J ⁡ ball ⁡ D ⁡ g ⁡ A + 1 ⊆ ball ⁡ D ⁡ g ⁡ A ∖ M ⁡ A
21 16 20 mpbid ⊢ φ ∧ A ∈ ℕ → g ⁡ A + 1 ∈ X × ℝ + ∧ 2 nd ⁡ g ⁡ A + 1 < 1 A ∧ cls ⁡ J ⁡ ball ⁡ D ⁡ g ⁡ A + 1 ⊆ ball ⁡ D ⁡ g ⁡ A ∖ M ⁡ A
22 21 simp3d ⊢ φ ∧ A ∈ ℕ → cls ⁡ J ⁡ ball ⁡ D ⁡ g ⁡ A + 1 ⊆ ball ⁡ D ⁡ g ⁡ A ∖ M ⁡ A
23 22 difss2d ⊢ φ ∧ A ∈ ℕ → cls ⁡ J ⁡ ball ⁡ D ⁡ g ⁡ A + 1 ⊆ ball ⁡ D ⁡ g ⁡ A
24 23 3adant2 ⊢ φ ∧ 1 st ∘ g ⇝t ⁡ J x ∧ A ∈ ℕ → cls ⁡ J ⁡ ball ⁡ D ⁡ g ⁡ A + 1 ⊆ ball ⁡ D ⁡ g ⁡ A
25 peano2nn ⊢ A ∈ ℕ → A + 1 ∈ ℕ
26 cmetmet ⊢ D ∈ CMet ⁡ X → D ∈ Met ⁡ X
27 metxmet ⊢ D ∈ Met ⁡ X → D ∈ ∞Met ⁡ X
28 2 26 27 3syl ⊢ φ → D ∈ ∞Met ⁡ X
29 1 2 3 4 5 6 7 8 9 bcthlem2 ⊢ φ → ∀ n ∈ ℕ ball ⁡ D ⁡ g ⁡ n + 1 ⊆ ball ⁡ D ⁡ g ⁡ n
30 28 7 29 1 caublcls ⊢ φ ∧ 1 st ∘ g ⇝t ⁡ J x ∧ A + 1 ∈ ℕ → x ∈ cls ⁡ J ⁡ ball ⁡ D ⁡ g ⁡ A + 1
31 25 30 syl3an3 ⊢ φ ∧ 1 st ∘ g ⇝t ⁡ J x ∧ A ∈ ℕ → x ∈ cls ⁡ J ⁡ ball ⁡ D ⁡ g ⁡ A + 1
32 24 31 sseldd ⊢ φ ∧ 1 st ∘ g ⇝t ⁡ J x ∧ A ∈ ℕ → x ∈ ball ⁡ D ⁡ g ⁡ A