Metamath Proof Explorer


Theorem blin

Description: The intersection of two balls with the same center is the smaller of them. (Contributed by NM, 1-Sep-2006) (Revised by Mario Carneiro, 12-Nov-2013)

Ref Expression
Assertion blin ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ * ∧ S ∈ ℝ * → P ball ⁡ D R ∩ P ball ⁡ D S = P ball ⁡ D if R ≤ S R S

Proof

Step Hyp Ref Expression
1 xmetcl ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ x ∈ X → P D x ∈ ℝ *
2 1 ad4ant124 ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ * ∧ S ∈ ℝ * ∧ x ∈ X → P D x ∈ ℝ *
3 simplrl ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ * ∧ S ∈ ℝ * ∧ x ∈ X → R ∈ ℝ *
4 simplrr ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ * ∧ S ∈ ℝ * ∧ x ∈ X → S ∈ ℝ *
5 xrltmin ⊢ P D x ∈ ℝ * ∧ R ∈ ℝ * ∧ S ∈ ℝ * → P D x < if R ≤ S R S ↔ P D x < R ∧ P D x < S
6 2 3 4 5 syl3anc ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ * ∧ S ∈ ℝ * ∧ x ∈ X → P D x < if R ≤ S R S ↔ P D x < R ∧ P D x < S
7 6 pm5.32da ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ * ∧ S ∈ ℝ * → x ∈ X ∧ P D x < if R ≤ S R S ↔ x ∈ X ∧ P D x < R ∧ P D x < S
8 ifcl ⊢ R ∈ ℝ * ∧ S ∈ ℝ * → if R ≤ S R S ∈ ℝ *
9 elbl ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ if R ≤ S R S ∈ ℝ * → x ∈ P ball ⁡ D if R ≤ S R S ↔ x ∈ X ∧ P D x < if R ≤ S R S
10 9 3expa ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ if R ≤ S R S ∈ ℝ * → x ∈ P ball ⁡ D if R ≤ S R S ↔ x ∈ X ∧ P D x < if R ≤ S R S
11 8 10 sylan2 ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ * ∧ S ∈ ℝ * → x ∈ P ball ⁡ D if R ≤ S R S ↔ x ∈ X ∧ P D x < if R ≤ S R S
12 elbl ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ * → x ∈ P ball ⁡ D R ↔ x ∈ X ∧ P D x < R
13 12 3expa ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ * → x ∈ P ball ⁡ D R ↔ x ∈ X ∧ P D x < R
14 13 adantrr ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ * ∧ S ∈ ℝ * → x ∈ P ball ⁡ D R ↔ x ∈ X ∧ P D x < R
15 elbl ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ S ∈ ℝ * → x ∈ P ball ⁡ D S ↔ x ∈ X ∧ P D x < S
16 15 3expa ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ S ∈ ℝ * → x ∈ P ball ⁡ D S ↔ x ∈ X ∧ P D x < S
17 16 adantrl ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ * ∧ S ∈ ℝ * → x ∈ P ball ⁡ D S ↔ x ∈ X ∧ P D x < S
18 14 17 anbi12d ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ * ∧ S ∈ ℝ * → x ∈ P ball ⁡ D R ∧ x ∈ P ball ⁡ D S ↔ x ∈ X ∧ P D x < R ∧ x ∈ X ∧ P D x < S
19 elin ⊢ x ∈ P ball ⁡ D R ∩ P ball ⁡ D S ↔ x ∈ P ball ⁡ D R ∧ x ∈ P ball ⁡ D S
20 anandi ⊢ x ∈ X ∧ P D x < R ∧ P D x < S ↔ x ∈ X ∧ P D x < R ∧ x ∈ X ∧ P D x < S
21 18 19 20 3bitr4g ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ * ∧ S ∈ ℝ * → x ∈ P ball ⁡ D R ∩ P ball ⁡ D S ↔ x ∈ X ∧ P D x < R ∧ P D x < S
22 7 11 21 3bitr4rd ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ * ∧ S ∈ ℝ * → x ∈ P ball ⁡ D R ∩ P ball ⁡ D S ↔ x ∈ P ball ⁡ D if R ≤ S R S
23 22 eqrdv ⊢ D ∈ ∞Met ⁡ X ∧ P ∈ X ∧ R ∈ ℝ * ∧ S ∈ ℝ * → P ball ⁡ D R ∩ P ball ⁡ D S = P ball ⁡ D if R ≤ S R S