Metamath Proof Explorer


Theorem bnj852

Description: Technical lemma for bnj69 . This lemma may no longer be used or have become an indirect lemma of the theorem in question (i.e. a lemma of a lemma... of the theorem). (Contributed by Jonathan Ben-Naim, 3-Jun-2011) (New usage is discouraged.)

Ref Expression
Hypotheses bnj852.1 ⊢ φ ↔ f ⁡ ∅ = pred X A R
bnj852.2 ⊢ ψ ↔ ∀ i ∈ ω suc ⁡ i ∈ n → f ⁡ suc ⁡ i = ⋃ y ∈ f ⁡ i pred y A R
bnj852.3 ⊢ D = ω ∖ ∅
Assertion bnj852 ⊢ R FrSe A ∧ X ∈ A → ∀ n ∈ D ∃! f f Fn n ∧ φ ∧ ψ

Proof

Step Hyp Ref Expression
1 bnj852.1 ⊢ φ ↔ f ⁡ ∅ = pred X A R
2 bnj852.2 ⊢ ψ ↔ ∀ i ∈ ω suc ⁡ i ∈ n → f ⁡ suc ⁡ i = ⋃ y ∈ f ⁡ i pred y A R
3 bnj852.3 ⊢ D = ω ∖ ∅
4 elisset ⊢ X ∈ A → ∃ x x = X
5 4 adantl ⊢ R FrSe A ∧ X ∈ A → ∃ x x = X
6 5 ancri ⊢ R FrSe A ∧ X ∈ A → ∃ x x = X ∧ R FrSe A ∧ X ∈ A
7 6 bnj534 ⊢ R FrSe A ∧ X ∈ A → ∃ x x = X ∧ R FrSe A ∧ X ∈ A
8 eleq1 ⊢ x = X → x ∈ A ↔ X ∈ A
9 8 anbi2d ⊢ x = X → R FrSe A ∧ x ∈ A ↔ R FrSe A ∧ X ∈ A
10 9 biimpar ⊢ x = X ∧ R FrSe A ∧ X ∈ A → R FrSe A ∧ x ∈ A
11 biid ⊢ ∀ z ∈ D z E n → [˙z / n]˙ R FrSe A ∧ x ∈ A → ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ ↔ ∀ z ∈ D z E n → [˙z / n]˙ R FrSe A ∧ x ∈ A → ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ
12 omex ⊢ ω ∈ V
13 difexg ⊢ ω ∈ V → ω ∖ ∅ ∈ V
14 12 13 ax-mp ⊢ ω ∖ ∅ ∈ V
15 3 14 eqeltri ⊢ D ∈ V
16 zfregfr ⊢ E Fr D
17 11 15 16 bnj157 ⊢ ∀ n ∈ D ∀ z ∈ D z E n → [˙z / n]˙ R FrSe A ∧ x ∈ A → ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ → R FrSe A ∧ x ∈ A → ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ → ∀ n ∈ D R FrSe A ∧ x ∈ A → ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ
18 biid ⊢ f ⁡ ∅ = pred x A R ↔ f ⁡ ∅ = pred x A R
19 biid ⊢ R FrSe A ∧ x ∈ A → ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ ↔ R FrSe A ∧ x ∈ A → ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ
20 18 2 3 19 11 bnj153 ⊢ n = 1 𝑜 → n ∈ D ∧ ∀ z ∈ D z E n → [˙z / n]˙ R FrSe A ∧ x ∈ A → ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ → R FrSe A ∧ x ∈ A → ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ
21 18 2 3 19 11 bnj601 ⊢ n ≠ 1 𝑜 → n ∈ D ∧ ∀ z ∈ D z E n → [˙z / n]˙ R FrSe A ∧ x ∈ A → ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ → R FrSe A ∧ x ∈ A → ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ
22 20 21 pm2.61ine ⊢ n ∈ D ∧ ∀ z ∈ D z E n → [˙z / n]˙ R FrSe A ∧ x ∈ A → ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ → R FrSe A ∧ x ∈ A → ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ
23 22 ex ⊢ n ∈ D → ∀ z ∈ D z E n → [˙z / n]˙ R FrSe A ∧ x ∈ A → ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ → R FrSe A ∧ x ∈ A → ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ
24 17 23 mprg ⊢ ∀ n ∈ D R FrSe A ∧ x ∈ A → ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ
25 r19.21v ⊢ ∀ n ∈ D R FrSe A ∧ x ∈ A → ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ ↔ R FrSe A ∧ x ∈ A → ∀ n ∈ D ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ
26 24 25 mpbi ⊢ R FrSe A ∧ x ∈ A → ∀ n ∈ D ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ
27 10 26 syl ⊢ x = X ∧ R FrSe A ∧ X ∈ A → ∀ n ∈ D ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ
28 bnj602 ⊢ x = X → pred x A R = pred X A R
29 28 eqeq2d ⊢ x = X → f ⁡ ∅ = pred x A R ↔ f ⁡ ∅ = pred X A R
30 29 1 bitr4di ⊢ x = X → f ⁡ ∅ = pred x A R ↔ φ
31 30 3anbi2d ⊢ x = X → f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ ↔ f Fn n ∧ φ ∧ ψ
32 31 eubidv ⊢ x = X → ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ ↔ ∃! f f Fn n ∧ φ ∧ ψ
33 32 ralbidv ⊢ x = X → ∀ n ∈ D ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ ↔ ∀ n ∈ D ∃! f f Fn n ∧ φ ∧ ψ
34 33 adantr ⊢ x = X ∧ R FrSe A ∧ X ∈ A → ∀ n ∈ D ∃! f f Fn n ∧ f ⁡ ∅ = pred x A R ∧ ψ ↔ ∀ n ∈ D ∃! f f Fn n ∧ φ ∧ ψ
35 27 34 mpbid ⊢ x = X ∧ R FrSe A ∧ X ∈ A → ∀ n ∈ D ∃! f f Fn n ∧ φ ∧ ψ
36 7 35 bnj593 ⊢ R FrSe A ∧ X ∈ A → ∃ x ∀ n ∈ D ∃! f f Fn n ∧ φ ∧ ψ
37 36 bnj937 ⊢ R FrSe A ∧ X ∈ A → ∀ n ∈ D ∃! f f Fn n ∧ φ ∧ ψ