Metamath Proof Explorer


Theorem caofcom

Description: Transfer a commutative law to the function operation. (Contributed by Mario Carneiro, 26-Jul-2014)

Ref Expression
Hypotheses caofref.1 ⊢ φ → A ∈ V
caofref.2 ⊢ φ → F : A ⟶ S
caofcom.3 ⊢ φ → G : A ⟶ S
caofcom.4 ⊢ φ ∧ x ∈ S ∧ y ∈ S → x R y = y R x
Assertion caofcom ⊢ φ → F R f G = G R f F

Proof

Step Hyp Ref Expression
1 caofref.1 ⊢ φ → A ∈ V
2 caofref.2 ⊢ φ → F : A ⟶ S
3 caofcom.3 ⊢ φ → G : A ⟶ S
4 caofcom.4 ⊢ φ ∧ x ∈ S ∧ y ∈ S → x R y = y R x
5 2 ffvelcdmda ⊢ φ ∧ w ∈ A → F ⁡ w ∈ S
6 3 ffvelcdmda ⊢ φ ∧ w ∈ A → G ⁡ w ∈ S
7 5 6 jca ⊢ φ ∧ w ∈ A → F ⁡ w ∈ S ∧ G ⁡ w ∈ S
8 4 caovcomg ⊢ φ ∧ F ⁡ w ∈ S ∧ G ⁡ w ∈ S → F ⁡ w R G ⁡ w = G ⁡ w R F ⁡ w
9 7 8 syldan ⊢ φ ∧ w ∈ A → F ⁡ w R G ⁡ w = G ⁡ w R F ⁡ w
10 9 mpteq2dva ⊢ φ → w ∈ A ⟼ F ⁡ w R G ⁡ w = w ∈ A ⟼ G ⁡ w R F ⁡ w
11 2 feqmptd ⊢ φ → F = w ∈ A ⟼ F ⁡ w
12 3 feqmptd ⊢ φ → G = w ∈ A ⟼ G ⁡ w
13 1 5 6 11 12 offval2 ⊢ φ → F R f G = w ∈ A ⟼ F ⁡ w R G ⁡ w
14 1 6 5 12 11 offval2 ⊢ φ → G R f F = w ∈ A ⟼ G ⁡ w R F ⁡ w
15 10 13 14 3eqtr4d ⊢ φ → F R f G = G R f F