Metamath Proof Explorer


Theorem cdleme

Description: Lemma E in Crawley p. 113. If p,q are atoms not under hyperplane w, then there is a unique translation f such that f(p) = q. (Contributed by NM, 11-Apr-2013)

Ref Expression
Hypotheses cdleme.l ⊢ ≤ ˙ = ≤ K
cdleme.a ⊢ A = Atoms ⁡ K
cdleme.h ⊢ H = LHyp ⁡ K
cdleme.t ⊢ T = LTrn ⁡ K ⁡ W
Assertion cdleme ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W → ∃! f ∈ T f ⁡ P = Q

Proof

Step Hyp Ref Expression
1 cdleme.l ⊢ ≤ ˙ = ≤ K
2 cdleme.a ⊢ A = Atoms ⁡ K
3 cdleme.h ⊢ H = LHyp ⁡ K
4 cdleme.t ⊢ T = LTrn ⁡ K ⁡ W
5 1 2 3 4 cdleme50ex ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W → ∃ f ∈ T f ⁡ P = Q
6 simp11 ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ f ∈ T ∧ z ∈ T ∧ f ⁡ P = Q ∧ z ⁡ P = Q → K ∈ HL ∧ W ∈ H
7 simp2l ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ f ∈ T ∧ z ∈ T ∧ f ⁡ P = Q ∧ z ⁡ P = Q → f ∈ T
8 simp2r ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ f ∈ T ∧ z ∈ T ∧ f ⁡ P = Q ∧ z ⁡ P = Q → z ∈ T
9 simp12 ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ f ∈ T ∧ z ∈ T ∧ f ⁡ P = Q ∧ z ⁡ P = Q → P ∈ A ∧ ¬ P ≤ ˙ W
10 eqtr3 ⊢ f ⁡ P = Q ∧ z ⁡ P = Q → f ⁡ P = z ⁡ P
11 10 3ad2ant3 ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ f ∈ T ∧ z ∈ T ∧ f ⁡ P = Q ∧ z ⁡ P = Q → f ⁡ P = z ⁡ P
12 1 2 3 4 cdlemd ⊢ K ∈ HL ∧ W ∈ H ∧ f ∈ T ∧ z ∈ T ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ f ⁡ P = z ⁡ P → f = z
13 6 7 8 9 11 12 syl311anc ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ f ∈ T ∧ z ∈ T ∧ f ⁡ P = Q ∧ z ⁡ P = Q → f = z
14 13 3exp ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W → f ∈ T ∧ z ∈ T → f ⁡ P = Q ∧ z ⁡ P = Q → f = z
15 14 ralrimivv ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W → ∀ f ∈ T ∀ z ∈ T f ⁡ P = Q ∧ z ⁡ P = Q → f = z
16 fveq1 ⊢ f = z → f ⁡ P = z ⁡ P
17 16 eqeq1d ⊢ f = z → f ⁡ P = Q ↔ z ⁡ P = Q
18 17 reu4 ⊢ ∃! f ∈ T f ⁡ P = Q ↔ ∃ f ∈ T f ⁡ P = Q ∧ ∀ f ∈ T ∀ z ∈ T f ⁡ P = Q ∧ z ⁡ P = Q → f = z
19 5 15 18 sylanbrc ⊢ K ∈ HL ∧ W ∈ H ∧ P ∈ A ∧ ¬ P ≤ ˙ W ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W → ∃! f ∈ T f ⁡ P = Q