Metamath Proof Explorer


Theorem cdlemkuu

Description: Convert between function and operation forms of Y . TODO: Use operation form everywhere. (Contributed by NM, 6-Jul-2013)

Ref Expression
Hypotheses cdlemk3.b ⊢ B = Base K
cdlemk3.l ⊢ ≤ ˙ = ≤ K
cdlemk3.j ⊢ ∨ ˙ = join ⁡ K
cdlemk3.m ⊢ ∧ ˙ = meet ⁡ K
cdlemk3.a ⊢ A = Atoms ⁡ K
cdlemk3.h ⊢ H = LHyp ⁡ K
cdlemk3.t ⊢ T = LTrn ⁡ K ⁡ W
cdlemk3.r ⊢ R = trL ⁡ K ⁡ W
cdlemk3.s ⊢ S = f ∈ T ⟼ ι i ∈ T | i ⁡ P = P ∨ ˙ R ⁡ f ∧ ˙ N ⁡ P ∨ ˙ R ⁡ f ∘ F -1
cdlemk3.u1 ⊢ Y = d ∈ T , e ∈ T ⟼ ι j ∈ T | j ⁡ P = P ∨ ˙ R ⁡ e ∧ ˙ S ⁡ d ⁡ P ∨ ˙ R ⁡ e ∘ d -1
cdlemk3.o2 ⊢ Q = S ⁡ D
cdlemk3.u2 ⊢ Z = e ∈ T ⟼ ι j ∈ T | j ⁡ P = P ∨ ˙ R ⁡ e ∧ ˙ Q ⁡ P ∨ ˙ R ⁡ e ∘ D -1
Assertion cdlemkuu ⊢ D ∈ T ∧ G ∈ T → D Y G = Z ⁡ G

Proof

Step Hyp Ref Expression
1 cdlemk3.b ⊢ B = Base K
2 cdlemk3.l ⊢ ≤ ˙ = ≤ K
3 cdlemk3.j ⊢ ∨ ˙ = join ⁡ K
4 cdlemk3.m ⊢ ∧ ˙ = meet ⁡ K
5 cdlemk3.a ⊢ A = Atoms ⁡ K
6 cdlemk3.h ⊢ H = LHyp ⁡ K
7 cdlemk3.t ⊢ T = LTrn ⁡ K ⁡ W
8 cdlemk3.r ⊢ R = trL ⁡ K ⁡ W
9 cdlemk3.s ⊢ S = f ∈ T ⟼ ι i ∈ T | i ⁡ P = P ∨ ˙ R ⁡ f ∧ ˙ N ⁡ P ∨ ˙ R ⁡ f ∘ F -1
10 cdlemk3.u1 ⊢ Y = d ∈ T , e ∈ T ⟼ ι j ∈ T | j ⁡ P = P ∨ ˙ R ⁡ e ∧ ˙ S ⁡ d ⁡ P ∨ ˙ R ⁡ e ∘ d -1
11 cdlemk3.o2 ⊢ Q = S ⁡ D
12 cdlemk3.u2 ⊢ Z = e ∈ T ⟼ ι j ∈ T | j ⁡ P = P ∨ ˙ R ⁡ e ∧ ˙ Q ⁡ P ∨ ˙ R ⁡ e ∘ D -1
13 fveq2 ⊢ d = D → S ⁡ d = S ⁡ D
14 13 11 eqtr4di ⊢ d = D → S ⁡ d = Q
15 14 fveq1d ⊢ d = D → S ⁡ d ⁡ P = Q ⁡ P
16 cnveq ⊢ d = D → d -1 = D -1
17 16 coeq2d ⊢ d = D → e ∘ d -1 = e ∘ D -1
18 17 fveq2d ⊢ d = D → R ⁡ e ∘ d -1 = R ⁡ e ∘ D -1
19 15 18 oveq12d ⊢ d = D → S ⁡ d ⁡ P ∨ ˙ R ⁡ e ∘ d -1 = Q ⁡ P ∨ ˙ R ⁡ e ∘ D -1
20 19 oveq2d ⊢ d = D → P ∨ ˙ R ⁡ e ∧ ˙ S ⁡ d ⁡ P ∨ ˙ R ⁡ e ∘ d -1 = P ∨ ˙ R ⁡ e ∧ ˙ Q ⁡ P ∨ ˙ R ⁡ e ∘ D -1
21 20 eqeq2d ⊢ d = D → j ⁡ P = P ∨ ˙ R ⁡ e ∧ ˙ S ⁡ d ⁡ P ∨ ˙ R ⁡ e ∘ d -1 ↔ j ⁡ P = P ∨ ˙ R ⁡ e ∧ ˙ Q ⁡ P ∨ ˙ R ⁡ e ∘ D -1
22 21 riotabidv ⊢ d = D → ι j ∈ T | j ⁡ P = P ∨ ˙ R ⁡ e ∧ ˙ S ⁡ d ⁡ P ∨ ˙ R ⁡ e ∘ d -1 = ι j ∈ T | j ⁡ P = P ∨ ˙ R ⁡ e ∧ ˙ Q ⁡ P ∨ ˙ R ⁡ e ∘ D -1
23 fveq2 ⊢ e = G → R ⁡ e = R ⁡ G
24 23 oveq2d ⊢ e = G → P ∨ ˙ R ⁡ e = P ∨ ˙ R ⁡ G
25 coeq1 ⊢ e = G → e ∘ D -1 = G ∘ D -1
26 25 fveq2d ⊢ e = G → R ⁡ e ∘ D -1 = R ⁡ G ∘ D -1
27 26 oveq2d ⊢ e = G → Q ⁡ P ∨ ˙ R ⁡ e ∘ D -1 = Q ⁡ P ∨ ˙ R ⁡ G ∘ D -1
28 24 27 oveq12d ⊢ e = G → P ∨ ˙ R ⁡ e ∧ ˙ Q ⁡ P ∨ ˙ R ⁡ e ∘ D -1 = P ∨ ˙ R ⁡ G ∧ ˙ Q ⁡ P ∨ ˙ R ⁡ G ∘ D -1
29 28 eqeq2d ⊢ e = G → j ⁡ P = P ∨ ˙ R ⁡ e ∧ ˙ Q ⁡ P ∨ ˙ R ⁡ e ∘ D -1 ↔ j ⁡ P = P ∨ ˙ R ⁡ G ∧ ˙ Q ⁡ P ∨ ˙ R ⁡ G ∘ D -1
30 29 riotabidv ⊢ e = G → ι j ∈ T | j ⁡ P = P ∨ ˙ R ⁡ e ∧ ˙ Q ⁡ P ∨ ˙ R ⁡ e ∘ D -1 = ι j ∈ T | j ⁡ P = P ∨ ˙ R ⁡ G ∧ ˙ Q ⁡ P ∨ ˙ R ⁡ G ∘ D -1
31 riotaex ⊢ ι j ∈ T | j ⁡ P = P ∨ ˙ R ⁡ G ∧ ˙ Q ⁡ P ∨ ˙ R ⁡ G ∘ D -1 ∈ V
32 22 30 10 31 ovmpo ⊢ D ∈ T ∧ G ∈ T → D Y G = ι j ∈ T | j ⁡ P = P ∨ ˙ R ⁡ G ∧ ˙ Q ⁡ P ∨ ˙ R ⁡ G ∘ D -1
33 1 2 3 5 6 7 8 4 12 cdlemksv ⊢ G ∈ T → Z ⁡ G = ι j ∈ T | j ⁡ P = P ∨ ˙ R ⁡ G ∧ ˙ Q ⁡ P ∨ ˙ R ⁡ G ∘ D -1
34 33 adantl ⊢ D ∈ T ∧ G ∈ T → Z ⁡ G = ι j ∈ T | j ⁡ P = P ∨ ˙ R ⁡ G ∧ ˙ Q ⁡ P ∨ ˙ R ⁡ G ∘ D -1
35 32 34 eqtr4d ⊢ D ∈ T ∧ G ∈ T → D Y G = Z ⁡ G