Metamath Proof Explorer


Theorem cgr3permute3

Description: Permutation law for three-place congruence. (Contributed by Scott Fenton, 5-Oct-2013)

Ref Expression
Assertion cgr3permute3 ⊢ N ∈ ℕ ∧ A ∈ 𝔼 ⁡ N ∧ B ∈ 𝔼 ⁡ N ∧ C ∈ 𝔼 ⁡ N ∧ D ∈ 𝔼 ⁡ N ∧ E ∈ 𝔼 ⁡ N ∧ F ∈ 𝔼 ⁡ N → A B C Cgr3 D E F ↔ B C A Cgr3 E F D

Proof

Step Hyp Ref Expression
1 id ⊢ N ∈ ℕ → N ∈ ℕ
2 3simpa ⊢ A ∈ 𝔼 ⁡ N ∧ B ∈ 𝔼 ⁡ N ∧ C ∈ 𝔼 ⁡ N → A ∈ 𝔼 ⁡ N ∧ B ∈ 𝔼 ⁡ N
3 3simpa ⊢ D ∈ 𝔼 ⁡ N ∧ E ∈ 𝔼 ⁡ N ∧ F ∈ 𝔼 ⁡ N → D ∈ 𝔼 ⁡ N ∧ E ∈ 𝔼 ⁡ N
4 cgrcomlr ⊢ N ∈ ℕ ∧ A ∈ 𝔼 ⁡ N ∧ B ∈ 𝔼 ⁡ N ∧ D ∈ 𝔼 ⁡ N ∧ E ∈ 𝔼 ⁡ N → A B Cgr D E ↔ B A Cgr E D
5 1 2 3 4 syl3an ⊢ N ∈ ℕ ∧ A ∈ 𝔼 ⁡ N ∧ B ∈ 𝔼 ⁡ N ∧ C ∈ 𝔼 ⁡ N ∧ D ∈ 𝔼 ⁡ N ∧ E ∈ 𝔼 ⁡ N ∧ F ∈ 𝔼 ⁡ N → A B Cgr D E ↔ B A Cgr E D
6 3simpb ⊢ A ∈ 𝔼 ⁡ N ∧ B ∈ 𝔼 ⁡ N ∧ C ∈ 𝔼 ⁡ N → A ∈ 𝔼 ⁡ N ∧ C ∈ 𝔼 ⁡ N
7 3simpb ⊢ D ∈ 𝔼 ⁡ N ∧ E ∈ 𝔼 ⁡ N ∧ F ∈ 𝔼 ⁡ N → D ∈ 𝔼 ⁡ N ∧ F ∈ 𝔼 ⁡ N
8 cgrcomlr ⊢ N ∈ ℕ ∧ A ∈ 𝔼 ⁡ N ∧ C ∈ 𝔼 ⁡ N ∧ D ∈ 𝔼 ⁡ N ∧ F ∈ 𝔼 ⁡ N → A C Cgr D F ↔ C A Cgr F D
9 1 6 7 8 syl3an ⊢ N ∈ ℕ ∧ A ∈ 𝔼 ⁡ N ∧ B ∈ 𝔼 ⁡ N ∧ C ∈ 𝔼 ⁡ N ∧ D ∈ 𝔼 ⁡ N ∧ E ∈ 𝔼 ⁡ N ∧ F ∈ 𝔼 ⁡ N → A C Cgr D F ↔ C A Cgr F D
10 5 9 3anbi12d ⊢ N ∈ ℕ ∧ A ∈ 𝔼 ⁡ N ∧ B ∈ 𝔼 ⁡ N ∧ C ∈ 𝔼 ⁡ N ∧ D ∈ 𝔼 ⁡ N ∧ E ∈ 𝔼 ⁡ N ∧ F ∈ 𝔼 ⁡ N → A B Cgr D E ∧ A C Cgr D F ∧ B C Cgr E F ↔ B A Cgr E D ∧ C A Cgr F D ∧ B C Cgr E F
11 3anrot ⊢ B C Cgr E F ∧ B A Cgr E D ∧ C A Cgr F D ↔ B A Cgr E D ∧ C A Cgr F D ∧ B C Cgr E F
12 10 11 bitr4di ⊢ N ∈ ℕ ∧ A ∈ 𝔼 ⁡ N ∧ B ∈ 𝔼 ⁡ N ∧ C ∈ 𝔼 ⁡ N ∧ D ∈ 𝔼 ⁡ N ∧ E ∈ 𝔼 ⁡ N ∧ F ∈ 𝔼 ⁡ N → A B Cgr D E ∧ A C Cgr D F ∧ B C Cgr E F ↔ B C Cgr E F ∧ B A Cgr E D ∧ C A Cgr F D
13 brcgr3 ⊢ N ∈ ℕ ∧ A ∈ 𝔼 ⁡ N ∧ B ∈ 𝔼 ⁡ N ∧ C ∈ 𝔼 ⁡ N ∧ D ∈ 𝔼 ⁡ N ∧ E ∈ 𝔼 ⁡ N ∧ F ∈ 𝔼 ⁡ N → A B C Cgr3 D E F ↔ A B Cgr D E ∧ A C Cgr D F ∧ B C Cgr E F
14 biid ⊢ N ∈ ℕ ↔ N ∈ ℕ
15 3anrot ⊢ A ∈ 𝔼 ⁡ N ∧ B ∈ 𝔼 ⁡ N ∧ C ∈ 𝔼 ⁡ N ↔ B ∈ 𝔼 ⁡ N ∧ C ∈ 𝔼 ⁡ N ∧ A ∈ 𝔼 ⁡ N
16 3anrot ⊢ D ∈ 𝔼 ⁡ N ∧ E ∈ 𝔼 ⁡ N ∧ F ∈ 𝔼 ⁡ N ↔ E ∈ 𝔼 ⁡ N ∧ F ∈ 𝔼 ⁡ N ∧ D ∈ 𝔼 ⁡ N
17 brcgr3 ⊢ N ∈ ℕ ∧ B ∈ 𝔼 ⁡ N ∧ C ∈ 𝔼 ⁡ N ∧ A ∈ 𝔼 ⁡ N ∧ E ∈ 𝔼 ⁡ N ∧ F ∈ 𝔼 ⁡ N ∧ D ∈ 𝔼 ⁡ N → B C A Cgr3 E F D ↔ B C Cgr E F ∧ B A Cgr E D ∧ C A Cgr F D
18 14 15 16 17 syl3anb ⊢ N ∈ ℕ ∧ A ∈ 𝔼 ⁡ N ∧ B ∈ 𝔼 ⁡ N ∧ C ∈ 𝔼 ⁡ N ∧ D ∈ 𝔼 ⁡ N ∧ E ∈ 𝔼 ⁡ N ∧ F ∈ 𝔼 ⁡ N → B C A Cgr3 E F D ↔ B C Cgr E F ∧ B A Cgr E D ∧ C A Cgr F D
19 12 13 18 3bitr4d ⊢ N ∈ ℕ ∧ A ∈ 𝔼 ⁡ N ∧ B ∈ 𝔼 ⁡ N ∧ C ∈ 𝔼 ⁡ N ∧ D ∈ 𝔼 ⁡ N ∧ E ∈ 𝔼 ⁡ N ∧ F ∈ 𝔼 ⁡ N → A B C Cgr3 D E F ↔ B C A Cgr3 E F D