Metamath Proof Explorer


Theorem cnsubrglem

Description: Lemma for resubdrg and friends. (Contributed by Mario Carneiro, 4-Dec-2014) Avoid ax-mulf . (Revised by GG, 30-Apr-2025)

Ref Expression
Hypotheses cnsubglem.1 ⊢ x ∈ A → x ∈ ℂ
cnsubglem.2 ⊢ x ∈ A ∧ y ∈ A → x + y ∈ A
cnsubglem.3 ⊢ x ∈ A → − x ∈ A
cnsubrglem.4 ⊢ 1 ∈ A
cnsubrglem.5 ⊢ x ∈ A ∧ y ∈ A → x ⁢ y ∈ A
Assertion cnsubrglem ⊢ A ∈ SubRing ⁡ ℂ fld

Proof

Step Hyp Ref Expression
1 cnsubglem.1 ⊢ x ∈ A → x ∈ ℂ
2 cnsubglem.2 ⊢ x ∈ A ∧ y ∈ A → x + y ∈ A
3 cnsubglem.3 ⊢ x ∈ A → − x ∈ A
4 cnsubrglem.4 ⊢ 1 ∈ A
5 cnsubrglem.5 ⊢ x ∈ A ∧ y ∈ A → x ⁢ y ∈ A
6 1 2 3 4 cnsubglem ⊢ A ∈ SubGrp ⁡ ℂ fld
7 1 adantr ⊢ x ∈ A ∧ y ∈ A → x ∈ ℂ
8 1 ax-gen ⊢ ∀ x x ∈ A → x ∈ ℂ
9 eleq1 ⊢ x = y → x ∈ A ↔ y ∈ A
10 eleq1 ⊢ x = y → x ∈ ℂ ↔ y ∈ ℂ
11 9 10 imbi12d ⊢ x = y → x ∈ A → x ∈ ℂ ↔ y ∈ A → y ∈ ℂ
12 11 spvv ⊢ ∀ x x ∈ A → x ∈ ℂ → y ∈ A → y ∈ ℂ
13 8 12 ax-mp ⊢ y ∈ A → y ∈ ℂ
14 13 adantl ⊢ x ∈ A ∧ y ∈ A → y ∈ ℂ
15 7 14 jca ⊢ x ∈ A ∧ y ∈ A → x ∈ ℂ ∧ y ∈ ℂ
16 ovmpot ⊢ x ∈ ℂ ∧ y ∈ ℂ → x u ∈ ℂ , v ∈ ℂ ⟼ u ⁢ v y = x ⁢ y
17 15 16 syl ⊢ x ∈ A ∧ y ∈ A → x u ∈ ℂ , v ∈ ℂ ⟼ u ⁢ v y = x ⁢ y
18 17 eqcomd ⊢ x ∈ A ∧ y ∈ A → x ⁢ y = x u ∈ ℂ , v ∈ ℂ ⟼ u ⁢ v y
19 18 eleq1d ⊢ x ∈ A ∧ y ∈ A → x ⁢ y ∈ A ↔ x u ∈ ℂ , v ∈ ℂ ⟼ u ⁢ v y ∈ A
20 5 19 mpbid ⊢ x ∈ A ∧ y ∈ A → x u ∈ ℂ , v ∈ ℂ ⟼ u ⁢ v y ∈ A
21 20 rgen2 ⊢ ∀ x ∈ A ∀ y ∈ A x u ∈ ℂ , v ∈ ℂ ⟼ u ⁢ v y ∈ A
22 cnring ⊢ ℂ fld ∈ Ring
23 cnfldbas ⊢ ℂ = Base ℂ fld
24 cnfld1 ⊢ 1 = 1 ℂ fld
25 mpocnfldmul ⊢ u ∈ ℂ , v ∈ ℂ ⟼ u ⁢ v = ⋅ ℂ fld
26 23 24 25 issubrg2 ⊢ ℂ fld ∈ Ring → A ∈ SubRing ⁡ ℂ fld ↔ A ∈ SubGrp ⁡ ℂ fld ∧ 1 ∈ A ∧ ∀ x ∈ A ∀ y ∈ A x u ∈ ℂ , v ∈ ℂ ⟼ u ⁢ v y ∈ A
27 22 26 ax-mp ⊢ A ∈ SubRing ⁡ ℂ fld ↔ A ∈ SubGrp ⁡ ℂ fld ∧ 1 ∈ A ∧ ∀ x ∈ A ∀ y ∈ A x u ∈ ℂ , v ∈ ℂ ⟼ u ⁢ v y ∈ A
28 6 4 21 27 mpbir3an ⊢ A ∈ SubRing ⁡ ℂ fld