Metamath Proof Explorer


Theorem deg1lt0

Description: A polynomial is zero iff it has negative degree. (Contributed by Stefan O'Rear, 1-Apr-2015)

Ref Expression
Hypotheses deg1z.d ⊢ D = deg 1 ⁡ R
deg1z.p ⊢ P = Poly 1 ⁡ R
deg1z.z ⊢ 0 ˙ = 0 P
deg1nn0cl.b ⊢ B = Base P
Assertion deg1lt0 ⊢ R ∈ Ring ∧ F ∈ B → D ⁡ F < 0 ↔ F = 0 ˙

Proof

Step Hyp Ref Expression
1 deg1z.d ⊢ D = deg 1 ⁡ R
2 deg1z.p ⊢ P = Poly 1 ⁡ R
3 deg1z.z ⊢ 0 ˙ = 0 P
4 deg1nn0cl.b ⊢ B = Base P
5 1 2 3 4 deg1nn0cl ⊢ R ∈ Ring ∧ F ∈ B ∧ F ≠ 0 ˙ → D ⁡ F ∈ ℕ 0
6 nn0nlt0 ⊢ D ⁡ F ∈ ℕ 0 → ¬ D ⁡ F < 0
7 5 6 syl ⊢ R ∈ Ring ∧ F ∈ B ∧ F ≠ 0 ˙ → ¬ D ⁡ F < 0
8 7 3expia ⊢ R ∈ Ring ∧ F ∈ B → F ≠ 0 ˙ → ¬ D ⁡ F < 0
9 8 necon4ad ⊢ R ∈ Ring ∧ F ∈ B → D ⁡ F < 0 → F = 0 ˙
10 1 2 3 deg1z ⊢ R ∈ Ring → D ⁡ 0 ˙ = −∞
11 mnflt0 ⊢ −∞ < 0
12 10 11 eqbrtrdi ⊢ R ∈ Ring → D ⁡ 0 ˙ < 0
13 12 adantr ⊢ R ∈ Ring ∧ F ∈ B → D ⁡ 0 ˙ < 0
14 fveq2 ⊢ F = 0 ˙ → D ⁡ F = D ⁡ 0 ˙
15 14 breq1d ⊢ F = 0 ˙ → D ⁡ F < 0 ↔ D ⁡ 0 ˙ < 0
16 13 15 syl5ibrcom ⊢ R ∈ Ring ∧ F ∈ B → F = 0 ˙ → D ⁡ F < 0
17 9 16 impbid ⊢ R ∈ Ring ∧ F ∈ B → D ⁡ F < 0 ↔ F = 0 ˙