Metamath Proof Explorer


Theorem dffrege115

Description: If from the circumstance that c is a result of an application of the procedure R to b , whatever b may be, it can be inferred that every result of an application of the procedure R to b is the same as c , then we say : "The procedure R is single-valued". Definition 115 of Frege1879 p. 77. (Contributed by RP, 7-Jul-2020)

Ref Expression
Assertion dffrege115 ⊢ ∀ c ∀ b b R c → ∀ a b R a → a = c ↔ Fun ⁡ R -1 -1

Proof

Step Hyp Ref Expression
1 alcom ⊢ ∀ c ∀ b b R c → ∀ a b R a → a = c ↔ ∀ b ∀ c b R c → ∀ a b R a → a = c
2 19.21v ⊢ ∀ a b R c → b R a → a = c ↔ b R c → ∀ a b R a → a = c
3 impexp ⊢ b R c ∧ b R a → a = c ↔ b R c → b R a → a = c
4 vex ⊢ b ∈ V
5 vex ⊢ c ∈ V
6 4 5 brcnv ⊢ b R -1 -1 c ↔ c R -1 b
7 df-br ⊢ b R -1 -1 c ↔ b c ∈ R -1 -1
8 5 4 brcnv ⊢ c R -1 b ↔ b R c
9 6 7 8 3bitr3ri ⊢ b R c ↔ b c ∈ R -1 -1
10 vex ⊢ a ∈ V
11 4 10 brcnv ⊢ b R -1 -1 a ↔ a R -1 b
12 df-br ⊢ b R -1 -1 a ↔ b a ∈ R -1 -1
13 10 4 brcnv ⊢ a R -1 b ↔ b R a
14 11 12 13 3bitr3ri ⊢ b R a ↔ b a ∈ R -1 -1
15 9 14 anbi12ci ⊢ b R c ∧ b R a ↔ b a ∈ R -1 -1 ∧ b c ∈ R -1 -1
16 15 imbi1i ⊢ b R c ∧ b R a → a = c ↔ b a ∈ R -1 -1 ∧ b c ∈ R -1 -1 → a = c
17 3 16 bitr3i ⊢ b R c → b R a → a = c ↔ b a ∈ R -1 -1 ∧ b c ∈ R -1 -1 → a = c
18 17 albii ⊢ ∀ a b R c → b R a → a = c ↔ ∀ a b a ∈ R -1 -1 ∧ b c ∈ R -1 -1 → a = c
19 2 18 bitr3i ⊢ b R c → ∀ a b R a → a = c ↔ ∀ a b a ∈ R -1 -1 ∧ b c ∈ R -1 -1 → a = c
20 19 albii ⊢ ∀ c b R c → ∀ a b R a → a = c ↔ ∀ c ∀ a b a ∈ R -1 -1 ∧ b c ∈ R -1 -1 → a = c
21 alcom ⊢ ∀ c ∀ a b a ∈ R -1 -1 ∧ b c ∈ R -1 -1 → a = c ↔ ∀ a ∀ c b a ∈ R -1 -1 ∧ b c ∈ R -1 -1 → a = c
22 20 21 bitri ⊢ ∀ c b R c → ∀ a b R a → a = c ↔ ∀ a ∀ c b a ∈ R -1 -1 ∧ b c ∈ R -1 -1 → a = c
23 opeq2 ⊢ a = c → b a = b c
24 23 eleq1d ⊢ a = c → b a ∈ R -1 -1 ↔ b c ∈ R -1 -1
25 24 mo4 ⊢ ∃* a b a ∈ R -1 -1 ↔ ∀ a ∀ c b a ∈ R -1 -1 ∧ b c ∈ R -1 -1 → a = c
26 dfmo ⊢ ∃* a b a ∈ R -1 -1 ↔ ∃ c ∀ a b a ∈ R -1 -1 → a = c
27 22 25 26 3bitr2i ⊢ ∀ c b R c → ∀ a b R a → a = c ↔ ∃ c ∀ a b a ∈ R -1 -1 → a = c
28 27 albii ⊢ ∀ b ∀ c b R c → ∀ a b R a → a = c ↔ ∀ b ∃ c ∀ a b a ∈ R -1 -1 → a = c
29 relcnv ⊢ Rel ⁡ R -1 -1
30 29 biantrur ⊢ ∀ b ∃ c ∀ a b a ∈ R -1 -1 → a = c ↔ Rel ⁡ R -1 -1 ∧ ∀ b ∃ c ∀ a b a ∈ R -1 -1 → a = c
31 dffun5 ⊢ Fun ⁡ R -1 -1 ↔ Rel ⁡ R -1 -1 ∧ ∀ b ∃ c ∀ a b a ∈ R -1 -1 → a = c
32 30 31 bitr4i ⊢ ∀ b ∃ c ∀ a b a ∈ R -1 -1 → a = c ↔ Fun ⁡ R -1 -1
33 1 28 32 3bitri ⊢ ∀ c ∀ b b R c → ∀ a b R a → a = c ↔ Fun ⁡ R -1 -1