Metamath Proof Explorer


Theorem dicelval1stN

Description: Membership in value of the partial isomorphism C for a lattice K . (Contributed by NM, 16-Feb-2014) (New usage is discouraged.)

Ref Expression
Hypotheses dicelval1st.l ⊢ ≤ ˙ = ≤ K
dicelval1st.a ⊢ A = Atoms ⁡ K
dicelval1st.h ⊢ H = LHyp ⁡ K
dicelval1st.t ⊢ T = LTrn ⁡ K ⁡ W
dicelval1st.i ⊢ I = DIsoC ⁡ K ⁡ W
Assertion dicelval1stN ⊢ K ∈ HL ∧ W ∈ H ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ Y ∈ I ⁡ Q → 1 st ⁡ Y ∈ T

Proof

Step Hyp Ref Expression
1 dicelval1st.l ⊢ ≤ ˙ = ≤ K
2 dicelval1st.a ⊢ A = Atoms ⁡ K
3 dicelval1st.h ⊢ H = LHyp ⁡ K
4 dicelval1st.t ⊢ T = LTrn ⁡ K ⁡ W
5 dicelval1st.i ⊢ I = DIsoC ⁡ K ⁡ W
6 eqid ⊢ DVecH ⁡ K ⁡ W = DVecH ⁡ K ⁡ W
7 eqid ⊢ Base DVecH ⁡ K ⁡ W = Base DVecH ⁡ K ⁡ W
8 1 2 3 5 6 7 dicssdvh ⊢ K ∈ HL ∧ W ∈ H ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W → I ⁡ Q ⊆ Base DVecH ⁡ K ⁡ W
9 eqid ⊢ TEndo ⁡ K ⁡ W = TEndo ⁡ K ⁡ W
10 3 4 9 6 7 dvhvbase ⊢ K ∈ HL ∧ W ∈ H → Base DVecH ⁡ K ⁡ W = T × TEndo ⁡ K ⁡ W
11 10 adantr ⊢ K ∈ HL ∧ W ∈ H ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W → Base DVecH ⁡ K ⁡ W = T × TEndo ⁡ K ⁡ W
12 8 11 sseqtrd ⊢ K ∈ HL ∧ W ∈ H ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W → I ⁡ Q ⊆ T × TEndo ⁡ K ⁡ W
13 12 sseld ⊢ K ∈ HL ∧ W ∈ H ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W → Y ∈ I ⁡ Q → Y ∈ T × TEndo ⁡ K ⁡ W
14 13 3impia ⊢ K ∈ HL ∧ W ∈ H ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ Y ∈ I ⁡ Q → Y ∈ T × TEndo ⁡ K ⁡ W
15 xp1st ⊢ Y ∈ T × TEndo ⁡ K ⁡ W → 1 st ⁡ Y ∈ T
16 14 15 syl ⊢ K ∈ HL ∧ W ∈ H ∧ Q ∈ A ∧ ¬ Q ≤ ˙ W ∧ Y ∈ I ⁡ Q → 1 st ⁡ Y ∈ T