Metamath Proof Explorer


Theorem dihcnvcl

Description: Closure of isomorphism H converse. (Contributed by NM, 8-Mar-2014)

Ref Expression
Hypotheses dihfn.b ⊢ B = Base K
dihfn.h ⊢ H = LHyp ⁡ K
dihfn.i ⊢ I = DIsoH ⁡ K ⁡ W
Assertion dihcnvcl ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ ran ⁡ I → I -1 ⁡ X ∈ B

Proof

Step Hyp Ref Expression
1 dihfn.b ⊢ B = Base K
2 dihfn.h ⊢ H = LHyp ⁡ K
3 dihfn.i ⊢ I = DIsoH ⁡ K ⁡ W
4 eqid ⊢ DVecH ⁡ K ⁡ W = DVecH ⁡ K ⁡ W
5 eqid ⊢ LSubSp ⁡ DVecH ⁡ K ⁡ W = LSubSp ⁡ DVecH ⁡ K ⁡ W
6 1 2 3 4 5 dihf11 ⊢ K ∈ HL ∧ W ∈ H → I : B ⟶ 1-1 LSubSp ⁡ DVecH ⁡ K ⁡ W
7 f1f1orn ⊢ I : B ⟶ 1-1 LSubSp ⁡ DVecH ⁡ K ⁡ W → I : B ⟶ 1-1 onto ran ⁡ I
8 6 7 syl ⊢ K ∈ HL ∧ W ∈ H → I : B ⟶ 1-1 onto ran ⁡ I
9 f1ocnvdm ⊢ I : B ⟶ 1-1 onto ran ⁡ I ∧ X ∈ ran ⁡ I → I -1 ⁡ X ∈ B
10 8 9 sylan ⊢ K ∈ HL ∧ W ∈ H ∧ X ∈ ran ⁡ I → I -1 ⁡ X ∈ B