Metamath Proof Explorer


Theorem dmfcoafv

Description: Domains of a function composition, analogous to dmfco . (Contributed by Alexander van der Vekens, 23-Jul-2017)

Ref Expression
Assertion dmfcoafv ⊢ Fun ⁡ G ∧ A ∈ dom ⁡ G → A ∈ dom ⁡ F ∘ G ↔ G ''' A ∈ dom ⁡ F

Proof

Step Hyp Ref Expression
1 dmfco ⊢ Fun ⁡ G ∧ A ∈ dom ⁡ G → A ∈ dom ⁡ F ∘ G ↔ G ⁡ A ∈ dom ⁡ F
2 funres ⊢ Fun ⁡ G → Fun ⁡ G ↾ A
3 2 anim2i ⊢ A ∈ dom ⁡ G ∧ Fun ⁡ G → A ∈ dom ⁡ G ∧ Fun ⁡ G ↾ A
4 3 ancoms ⊢ Fun ⁡ G ∧ A ∈ dom ⁡ G → A ∈ dom ⁡ G ∧ Fun ⁡ G ↾ A
5 df-dfat ⊢ G defAt A ↔ A ∈ dom ⁡ G ∧ Fun ⁡ G ↾ A
6 afvfundmfveq ⊢ G defAt A → G ''' A = G ⁡ A
7 5 6 sylbir ⊢ A ∈ dom ⁡ G ∧ Fun ⁡ G ↾ A → G ''' A = G ⁡ A
8 4 7 syl ⊢ Fun ⁡ G ∧ A ∈ dom ⁡ G → G ''' A = G ⁡ A
9 8 eqcomd ⊢ Fun ⁡ G ∧ A ∈ dom ⁡ G → G ⁡ A = G ''' A
10 9 eleq1d ⊢ Fun ⁡ G ∧ A ∈ dom ⁡ G → G ⁡ A ∈ dom ⁡ F ↔ G ''' A ∈ dom ⁡ F
11 1 10 bitrd ⊢ Fun ⁡ G ∧ A ∈ dom ⁡ G → A ∈ dom ⁡ F ∘ G ↔ G ''' A ∈ dom ⁡ F