Metamath Proof Explorer


Theorem dmgmdivn0

Description: Lemma for lgamf . (Contributed by Mario Carneiro, 3-Jul-2017)

Ref Expression
Hypotheses dmgmn0.a ⊢ φ → A ∈ ℂ ∖ ℤ ∖ ℕ
dmgmdivn0.a ⊢ φ → M ∈ ℕ
Assertion dmgmdivn0 ⊢ φ → A M + 1 ≠ 0

Proof

Step Hyp Ref Expression
1 dmgmn0.a ⊢ φ → A ∈ ℂ ∖ ℤ ∖ ℕ
2 dmgmdivn0.a ⊢ φ → M ∈ ℕ
3 1 eldifad ⊢ φ → A ∈ ℂ
4 2 nncnd ⊢ φ → M ∈ ℂ
5 2 nnne0d ⊢ φ → M ≠ 0
6 3 4 4 5 divdird ⊢ φ → A + M M = A M + M M
7 4 5 dividd ⊢ φ → M M = 1
8 7 oveq2d ⊢ φ → A M + M M = A M + 1
9 6 8 eqtrd ⊢ φ → A + M M = A M + 1
10 3 4 addcld ⊢ φ → A + M ∈ ℂ
11 2 nnnn0d ⊢ φ → M ∈ ℕ 0
12 dmgmaddn0 ⊢ A ∈ ℂ ∖ ℤ ∖ ℕ ∧ M ∈ ℕ 0 → A + M ≠ 0
13 1 11 12 syl2anc ⊢ φ → A + M ≠ 0
14 10 4 13 5 divne0d ⊢ φ → A + M M ≠ 0
15 9 14 eqnetrrd ⊢ φ → A M + 1 ≠ 0