Metamath Proof Explorer


Theorem dmtrclfv

Description: The domain of the transitive closure is equal to the domain of the relation. (Contributed by RP, 9-May-2020)

Ref Expression
Assertion dmtrclfv ⊢ R ∈ V → dom ⁡ t+ ⁡ R = dom ⁡ R

Proof

Step Hyp Ref Expression
1 trclfvub ⊢ R ∈ V → t+ ⁡ R ⊆ R ∪ dom ⁡ R × ran ⁡ R
2 dmss ⊢ t+ ⁡ R ⊆ R ∪ dom ⁡ R × ran ⁡ R → dom ⁡ t+ ⁡ R ⊆ dom ⁡ R ∪ dom ⁡ R × ran ⁡ R
3 1 2 syl ⊢ R ∈ V → dom ⁡ t+ ⁡ R ⊆ dom ⁡ R ∪ dom ⁡ R × ran ⁡ R
4 dmun ⊢ dom ⁡ R ∪ dom ⁡ R × ran ⁡ R = dom ⁡ R ∪ dom ⁡ dom ⁡ R × ran ⁡ R
5 dm0rn0 ⊢ dom ⁡ R = ∅ ↔ ran ⁡ R = ∅
6 xpeq1 ⊢ dom ⁡ R = ∅ → dom ⁡ R × ran ⁡ R = ∅ × ran ⁡ R
7 0xp ⊢ ∅ × ran ⁡ R = ∅
8 6 7 eqtrdi ⊢ dom ⁡ R = ∅ → dom ⁡ R × ran ⁡ R = ∅
9 8 dmeqd ⊢ dom ⁡ R = ∅ → dom ⁡ dom ⁡ R × ran ⁡ R = dom ⁡ ∅
10 dm0 ⊢ dom ⁡ ∅ = ∅
11 10 a1i ⊢ dom ⁡ R = ∅ → dom ⁡ ∅ = ∅
12 eqcom ⊢ dom ⁡ R = ∅ ↔ ∅ = dom ⁡ R
13 12 biimpi ⊢ dom ⁡ R = ∅ → ∅ = dom ⁡ R
14 9 11 13 3eqtrd ⊢ dom ⁡ R = ∅ → dom ⁡ dom ⁡ R × ran ⁡ R = dom ⁡ R
15 5 14 sylbir ⊢ ran ⁡ R = ∅ → dom ⁡ dom ⁡ R × ran ⁡ R = dom ⁡ R
16 dmxp ⊢ ran ⁡ R ≠ ∅ → dom ⁡ dom ⁡ R × ran ⁡ R = dom ⁡ R
17 15 16 pm2.61ine ⊢ dom ⁡ dom ⁡ R × ran ⁡ R = dom ⁡ R
18 17 uneq2i ⊢ dom ⁡ R ∪ dom ⁡ dom ⁡ R × ran ⁡ R = dom ⁡ R ∪ dom ⁡ R
19 unidm ⊢ dom ⁡ R ∪ dom ⁡ R = dom ⁡ R
20 4 18 19 3eqtri ⊢ dom ⁡ R ∪ dom ⁡ R × ran ⁡ R = dom ⁡ R
21 3 20 sseqtrdi ⊢ R ∈ V → dom ⁡ t+ ⁡ R ⊆ dom ⁡ R
22 trclfvlb ⊢ R ∈ V → R ⊆ t+ ⁡ R
23 dmss ⊢ R ⊆ t+ ⁡ R → dom ⁡ R ⊆ dom ⁡ t+ ⁡ R
24 22 23 syl ⊢ R ∈ V → dom ⁡ R ⊆ dom ⁡ t+ ⁡ R
25 21 24 eqssd ⊢ R ∈ V → dom ⁡ t+ ⁡ R = dom ⁡ R