Metamath Proof Explorer


Theorem drnginvrcl

Description: Closure of the multiplicative inverse in a division ring. ( reccl analog). (Contributed by NM, 19-Apr-2014)

Ref Expression
Hypotheses drnginvrcl.b ⊢ B = Base R
drnginvrcl.z ⊢ 0 ˙ = 0 R
drnginvrcl.i ⊢ I = inv r ⁡ R
Assertion drnginvrcl ⊢ R ∈ DivRing ∧ X ∈ B ∧ X ≠ 0 ˙ → I ⁡ X ∈ B

Proof

Step Hyp Ref Expression
1 drnginvrcl.b ⊢ B = Base R
2 drnginvrcl.z ⊢ 0 ˙ = 0 R
3 drnginvrcl.i ⊢ I = inv r ⁡ R
4 eqid ⊢ Unit ⁡ R = Unit ⁡ R
5 1 4 2 drngunit ⊢ R ∈ DivRing → X ∈ Unit ⁡ R ↔ X ∈ B ∧ X ≠ 0 ˙
6 drngring ⊢ R ∈ DivRing → R ∈ Ring
7 4 3 1 ringinvcl ⊢ R ∈ Ring ∧ X ∈ Unit ⁡ R → I ⁡ X ∈ B
8 7 ex ⊢ R ∈ Ring → X ∈ Unit ⁡ R → I ⁡ X ∈ B
9 6 8 syl ⊢ R ∈ DivRing → X ∈ Unit ⁡ R → I ⁡ X ∈ B
10 5 9 sylbird ⊢ R ∈ DivRing → X ∈ B ∧ X ≠ 0 ˙ → I ⁡ X ∈ B
11 10 3impib ⊢ R ∈ DivRing ∧ X ∈ B ∧ X ≠ 0 ˙ → I ⁡ X ∈ B