Metamath Proof Explorer


Theorem elabrexg

Description: Elementhood in an image set. (Contributed by Glauco Siliprandi, 11-Dec-2019)

Ref Expression
Assertion elabrexg ⊢ x ∈ A ∧ B ∈ V → B ∈ y | ∃ x ∈ A y = B

Proof

Step Hyp Ref Expression
1 tru ⊢ ⊤
2 csbeq1a ⊢ x = z → B = ⦋ z / x⦌ B
3 2 equcoms ⊢ z = x → B = ⦋ z / x⦌ B
4 trud ⊢ z = x → ⊤
5 3 4 2thd ⊢ z = x → B = ⦋ z / x⦌ B ↔ ⊤
6 5 rspcev ⊢ x ∈ A ∧ ⊤ → ∃ z ∈ A B = ⦋ z / x⦌ B
7 1 6 mpan2 ⊢ x ∈ A → ∃ z ∈ A B = ⦋ z / x⦌ B
8 7 adantr ⊢ x ∈ A ∧ B ∈ V → ∃ z ∈ A B = ⦋ z / x⦌ B
9 eqeq1 ⊢ y = B → y = ⦋ z / x⦌ B ↔ B = ⦋ z / x⦌ B
10 9 rexbidv ⊢ y = B → ∃ z ∈ A y = ⦋ z / x⦌ B ↔ ∃ z ∈ A B = ⦋ z / x⦌ B
11 10 elabg ⊢ B ∈ V → B ∈ y | ∃ z ∈ A y = ⦋ z / x⦌ B ↔ ∃ z ∈ A B = ⦋ z / x⦌ B
12 11 adantl ⊢ x ∈ A ∧ B ∈ V → B ∈ y | ∃ z ∈ A y = ⦋ z / x⦌ B ↔ ∃ z ∈ A B = ⦋ z / x⦌ B
13 8 12 mpbird ⊢ x ∈ A ∧ B ∈ V → B ∈ y | ∃ z ∈ A y = ⦋ z / x⦌ B
14 nfv ⊢ Ⅎ z y = B
15 nfcsb1v ⊢ Ⅎ _ x ⦋ z / x⦌ B
16 15 nfeq2 ⊢ Ⅎ x y = ⦋ z / x⦌ B
17 2 eqeq2d ⊢ x = z → y = B ↔ y = ⦋ z / x⦌ B
18 14 16 17 cbvrexw ⊢ ∃ x ∈ A y = B ↔ ∃ z ∈ A y = ⦋ z / x⦌ B
19 18 abbii ⊢ y | ∃ x ∈ A y = B = y | ∃ z ∈ A y = ⦋ z / x⦌ B
20 13 19 eleqtrrdi ⊢ x ∈ A ∧ B ∈ V → B ∈ y | ∃ x ∈ A y = B