Metamath Proof Explorer


Theorem evl1at1

Description: Polynomial evaluation for the 1 scalar. (Contributed by AV, 10-Aug-2019)

Ref Expression
Hypotheses evl1at0.o ⊢ O = eval 1 ⁡ R
evl1at0.p ⊢ P = Poly 1 ⁡ R
evl1at1.1 ⊢ 1 ˙ = 1 R
evl1at1.i ⊢ I = 1 P
Assertion evl1at1 ⊢ R ∈ CRing → O ⁡ I ⁡ 1 ˙ = 1 ˙

Proof

Step Hyp Ref Expression
1 evl1at0.o ⊢ O = eval 1 ⁡ R
2 evl1at0.p ⊢ P = Poly 1 ⁡ R
3 evl1at1.1 ⊢ 1 ˙ = 1 R
4 evl1at1.i ⊢ I = 1 P
5 crngring ⊢ R ∈ CRing → R ∈ Ring
6 eqid ⊢ algSc ⁡ P = algSc ⁡ P
7 2 6 3 4 ply1scl1 ⊢ R ∈ Ring → algSc ⁡ P ⁡ 1 ˙ = I
8 5 7 syl ⊢ R ∈ CRing → algSc ⁡ P ⁡ 1 ˙ = I
9 8 eqcomd ⊢ R ∈ CRing → I = algSc ⁡ P ⁡ 1 ˙
10 9 fveq2d ⊢ R ∈ CRing → O ⁡ I = O ⁡ algSc ⁡ P ⁡ 1 ˙
11 10 fveq1d ⊢ R ∈ CRing → O ⁡ I ⁡ 1 ˙ = O ⁡ algSc ⁡ P ⁡ 1 ˙ ⁡ 1 ˙
12 eqid ⊢ Base R = Base R
13 eqid ⊢ Base P = Base P
14 id ⊢ R ∈ CRing → R ∈ CRing
15 12 3 ringidcl ⊢ R ∈ Ring → 1 ˙ ∈ Base R
16 5 15 syl ⊢ R ∈ CRing → 1 ˙ ∈ Base R
17 1 2 12 6 13 14 16 16 evl1scad ⊢ R ∈ CRing → algSc ⁡ P ⁡ 1 ˙ ∈ Base P ∧ O ⁡ algSc ⁡ P ⁡ 1 ˙ ⁡ 1 ˙ = 1 ˙
18 17 simprd ⊢ R ∈ CRing → O ⁡ algSc ⁡ P ⁡ 1 ˙ ⁡ 1 ˙ = 1 ˙
19 11 18 eqtrd ⊢ R ∈ CRing → O ⁡ I ⁡ 1 ˙ = 1 ˙