Metamath Proof Explorer


Theorem expsval

Description: The value of surreal exponentiation. (Contributed by Scott Fenton, 24-Jul-2025)

Ref Expression
Assertion expsval Could not format assertion : No typesetting found for |- ( ( A e. No /\ B e. ZZ_s ) -> ( A ^su B ) = if ( B = 0s , 1s , if ( 0s

Proof

Step Hyp Ref Expression
1 eqidd ⊢ x = A → 1 s = 1 s
2 eqidd ⊢ x = A → ⋅ s = ⋅ s
3 sneq ⊢ x = A → x = A
4 3 xpeq2d ⊢ x = A → ℕ s × x = ℕ s × A
5 1 2 4 seqseq123d ⊢ x = A → seq s 1 s ⋅ s ℕ s × x = seq s 1 s ⋅ s ℕ s × A
6 5 fveq1d ⊢ x = A → seq s 1 s ⋅ s ℕ s × x ⁡ y = seq s 1 s ⋅ s ℕ s × A ⁡ y
7 5 fveq1d ⊢ x = A → seq s 1 s ⋅ s ℕ s × x ⁡ + s ⁡ y = seq s 1 s ⋅ s ℕ s × A ⁡ + s ⁡ y
8 7 oveq2d ⊢ x = A → 1 s / su seq s 1 s ⋅ s ℕ s × x ⁡ + s ⁡ y = 1 s / su seq s 1 s ⋅ s ℕ s × A ⁡ + s ⁡ y
9 6 8 ifeq12d ⊢ x = A → if 0 s < s y seq s 1 s ⋅ s ℕ s × x ⁡ y 1 s / su seq s 1 s ⋅ s ℕ s × x ⁡ + s ⁡ y = if 0 s < s y seq s 1 s ⋅ s ℕ s × A ⁡ y 1 s / su seq s 1 s ⋅ s ℕ s × A ⁡ + s ⁡ y
10 9 ifeq2d ⊢ x = A → if y = 0 s 1 s if 0 s < s y seq s 1 s ⋅ s ℕ s × x ⁡ y 1 s / su seq s 1 s ⋅ s ℕ s × x ⁡ + s ⁡ y = if y = 0 s 1 s if 0 s < s y seq s 1 s ⋅ s ℕ s × A ⁡ y 1 s / su seq s 1 s ⋅ s ℕ s × A ⁡ + s ⁡ y
11 eqeq1 ⊢ y = B → y = 0 s ↔ B = 0 s
12 breq2 ⊢ y = B → 0 s < s y ↔ 0 s < s B
13 fveq2 ⊢ y = B → seq s 1 s ⋅ s ℕ s × A ⁡ y = seq s 1 s ⋅ s ℕ s × A ⁡ B
14 2fveq3 ⊢ y = B → seq s 1 s ⋅ s ℕ s × A ⁡ + s ⁡ y = seq s 1 s ⋅ s ℕ s × A ⁡ + s ⁡ B
15 14 oveq2d ⊢ y = B → 1 s / su seq s 1 s ⋅ s ℕ s × A ⁡ + s ⁡ y = 1 s / su seq s 1 s ⋅ s ℕ s × A ⁡ + s ⁡ B
16 12 13 15 ifbieq12d ⊢ y = B → if 0 s < s y seq s 1 s ⋅ s ℕ s × A ⁡ y 1 s / su seq s 1 s ⋅ s ℕ s × A ⁡ + s ⁡ y = if 0 s < s B seq s 1 s ⋅ s ℕ s × A ⁡ B 1 s / su seq s 1 s ⋅ s ℕ s × A ⁡ + s ⁡ B
17 11 16 ifbieq2d ⊢ y = B → if y = 0 s 1 s if 0 s < s y seq s 1 s ⋅ s ℕ s × A ⁡ y 1 s / su seq s 1 s ⋅ s ℕ s × A ⁡ + s ⁡ y = if B = 0 s 1 s if 0 s < s B seq s 1 s ⋅ s ℕ s × A ⁡ B 1 s / su seq s 1 s ⋅ s ℕ s × A ⁡ + s ⁡ B
18 df-exps Could not format ^su = ( x e. No , y e. ZZ_s |-> if ( y = 0s , 1s , if ( 0s if ( y = 0s , 1s , if ( 0s
19 1no ⊢ 1 s ∈ No
20 19 elexi ⊢ 1 s ∈ V
21 fvex ⊢ seq s 1 s ⋅ s ℕ s × A ⁡ B ∈ V
22 ovex ⊢ 1 s / su seq s 1 s ⋅ s ℕ s × A ⁡ + s ⁡ B ∈ V
23 21 22 ifex ⊢ if 0 s < s B seq s 1 s ⋅ s ℕ s × A ⁡ B 1 s / su seq s 1 s ⋅ s ℕ s × A ⁡ + s ⁡ B ∈ V
24 20 23 ifex ⊢ if B = 0 s 1 s if 0 s < s B seq s 1 s ⋅ s ℕ s × A ⁡ B 1 s / su seq s 1 s ⋅ s ℕ s × A ⁡ + s ⁡ B ∈ V
25 10 17 18 24 ovmpo Could not format ( ( A e. No /\ B e. ZZ_s ) -> ( A ^su B ) = if ( B = 0s , 1s , if ( 0s ( A ^su B ) = if ( B = 0s , 1s , if ( 0s