Metamath Proof Explorer


Theorem f1fi

Description: If a 1-to-1 function has a finite codomain its domain is finite. (Contributed by FL, 31-Jul-2009) (Revised by Mario Carneiro, 24-Jun-2015)

Ref Expression
Assertion f1fi ⊢ B ∈ Fin ∧ F : A ⟶ 1-1 B → A ∈ Fin

Proof

Step Hyp Ref Expression
1 f1f ⊢ F : A ⟶ 1-1 B → F : A ⟶ B
2 1 frnd ⊢ F : A ⟶ 1-1 B → ran ⁡ F ⊆ B
3 ssfi ⊢ B ∈ Fin ∧ ran ⁡ F ⊆ B → ran ⁡ F ∈ Fin
4 2 3 sylan2 ⊢ B ∈ Fin ∧ F : A ⟶ 1-1 B → ran ⁡ F ∈ Fin
5 f1f1orn ⊢ F : A ⟶ 1-1 B → F : A ⟶ 1-1 onto ran ⁡ F
6 5 adantl ⊢ B ∈ Fin ∧ F : A ⟶ 1-1 B → F : A ⟶ 1-1 onto ran ⁡ F
7 f1ocnv ⊢ F : A ⟶ 1-1 onto ran ⁡ F → F -1 : ran ⁡ F ⟶ 1-1 onto A
8 f1ofo ⊢ F -1 : ran ⁡ F ⟶ 1-1 onto A → F -1 : ran ⁡ F ⟶ onto A
9 6 7 8 3syl ⊢ B ∈ Fin ∧ F : A ⟶ 1-1 B → F -1 : ran ⁡ F ⟶ onto A
10 fofi ⊢ ran ⁡ F ∈ Fin ∧ F -1 : ran ⁡ F ⟶ onto A → A ∈ Fin
11 4 9 10 syl2anc ⊢ B ∈ Fin ∧ F : A ⟶ 1-1 B → A ∈ Fin