Metamath Proof Explorer


Theorem f1oen3g

Description: The domain and range of a one-to-one, onto set function are equinumerous. This variation of f1oeng does not require the Axiom of Replacement nor the Axiom of Power Sets. (Contributed by NM, 13-Jan-2007) (Revised by Mario Carneiro, 10-Sep-2015)

Ref Expression
Assertion f1oen3g ⊢ F ∈ V ∧ F : A ⟶ 1-1 onto B → A ≈ B

Proof

Step Hyp Ref Expression
1 f1oeq1 ⊢ f = F → f : A ⟶ 1-1 onto B ↔ F : A ⟶ 1-1 onto B
2 1 spcegv ⊢ F ∈ V → F : A ⟶ 1-1 onto B → ∃ f f : A ⟶ 1-1 onto B
3 2 imp ⊢ F ∈ V ∧ F : A ⟶ 1-1 onto B → ∃ f f : A ⟶ 1-1 onto B
4 bren ⊢ A ≈ B ↔ ∃ f f : A ⟶ 1-1 onto B
5 3 4 sylibr ⊢ F ∈ V ∧ F : A ⟶ 1-1 onto B → A ≈ B