Metamath Proof Explorer


Theorem f1oen3g

Description: The domain and range of a one-to-one, onto set function are equinumerous. This variation of f1oeng does not require the Axiom of Replacement nor the Axiom of Power Sets. (Contributed by NM, 13-Jan-2007) (Revised by Mario Carneiro, 10-Sep-2015)

Ref Expression
Assertion f1oen3g FVF:A1-1 ontoBAB

Proof

Step Hyp Ref Expression
1 f1oeq1 f=Ff:A1-1 ontoBF:A1-1 ontoB
2 1 spcegv FVF:A1-1 ontoBff:A1-1 ontoB
3 2 imp FVF:A1-1 ontoBff:A1-1 ontoB
4 bren ABff:A1-1 ontoB
5 3 4 sylibr FVF:A1-1 ontoBAB