Metamath Proof Explorer


Theorem f1osng

Description: A singleton of an ordered pair is one-to-one onto function. (Contributed by Mario Carneiro, 12-Jan-2013)

Ref Expression
Assertion f1osng ⊢ A ∈ V ∧ B ∈ W → A B : A ⟶ 1-1 onto B

Proof

Step Hyp Ref Expression
1 sneq ⊢ a = A → a = A
2 1 f1oeq2d ⊢ a = A → a b : a ⟶ 1-1 onto b ↔ a b : A ⟶ 1-1 onto b
3 opeq1 ⊢ a = A → a b = A b
4 3 sneqd ⊢ a = A → a b = A b
5 4 f1oeq1d ⊢ a = A → a b : A ⟶ 1-1 onto b ↔ A b : A ⟶ 1-1 onto b
6 2 5 bitrd ⊢ a = A → a b : a ⟶ 1-1 onto b ↔ A b : A ⟶ 1-1 onto b
7 sneq ⊢ b = B → b = B
8 7 f1oeq3d ⊢ b = B → A b : A ⟶ 1-1 onto b ↔ A b : A ⟶ 1-1 onto B
9 opeq2 ⊢ b = B → A b = A B
10 9 sneqd ⊢ b = B → A b = A B
11 10 f1oeq1d ⊢ b = B → A b : A ⟶ 1-1 onto B ↔ A B : A ⟶ 1-1 onto B
12 8 11 bitrd ⊢ b = B → A b : A ⟶ 1-1 onto b ↔ A B : A ⟶ 1-1 onto B
13 vex ⊢ a ∈ V
14 vex ⊢ b ∈ V
15 13 14 f1osn ⊢ a b : a ⟶ 1-1 onto b
16 6 12 15 vtocl2g ⊢ A ∈ V ∧ B ∈ W → A B : A ⟶ 1-1 onto B