Metamath Proof Explorer


Theorem fallfaccllem

Description: Lemma for falling factorial closure laws. (Contributed by Scott Fenton, 5-Jan-2018)

Ref Expression
Hypotheses risefallfaccllem.1 ⊢ S ⊆ ℂ
risefallfaccllem.2 ⊢ 1 ∈ S
risefallfaccllem.3 ⊢ x ∈ S ∧ y ∈ S → x ⁢ y ∈ S
fallfaccllem.4 ⊢ A ∈ S ∧ k ∈ ℕ 0 → A − k ∈ S
Assertion fallfaccllem ⊢ A ∈ S ∧ N ∈ ℕ 0 → A N _ ∈ S

Proof

Step Hyp Ref Expression
1 risefallfaccllem.1 ⊢ S ⊆ ℂ
2 risefallfaccllem.2 ⊢ 1 ∈ S
3 risefallfaccllem.3 ⊢ x ∈ S ∧ y ∈ S → x ⁢ y ∈ S
4 fallfaccllem.4 ⊢ A ∈ S ∧ k ∈ ℕ 0 → A − k ∈ S
5 1 sseli ⊢ A ∈ S → A ∈ ℂ
6 fallfacval ⊢ A ∈ ℂ ∧ N ∈ ℕ 0 → A N _ = ∏ k = 0 N − 1 A − k
7 5 6 sylan ⊢ A ∈ S ∧ N ∈ ℕ 0 → A N _ = ∏ k = 0 N − 1 A − k
8 1 a1i ⊢ A ∈ S → S ⊆ ℂ
9 3 adantl ⊢ A ∈ S ∧ x ∈ S ∧ y ∈ S → x ⁢ y ∈ S
10 fzfid ⊢ A ∈ S → 0 … N − 1 ∈ Fin
11 elfznn0 ⊢ k ∈ 0 … N − 1 → k ∈ ℕ 0
12 11 4 sylan2 ⊢ A ∈ S ∧ k ∈ 0 … N − 1 → A − k ∈ S
13 2 a1i ⊢ A ∈ S → 1 ∈ S
14 8 9 10 12 13 fprodcllem ⊢ A ∈ S → ∏ k = 0 N − 1 A − k ∈ S
15 14 adantr ⊢ A ∈ S ∧ N ∈ ℕ 0 → ∏ k = 0 N − 1 A − k ∈ S
16 7 15 eqeltrd ⊢ A ∈ S ∧ N ∈ ℕ 0 → A N _ ∈ S