Metamath Proof Explorer


Theorem fallfacfac

Description: Relate falling factorial to factorial. (Contributed by Scott Fenton, 5-Jan-2018)

Ref Expression
Assertion fallfacfac ⊢ N ∈ ℕ 0 → N N _ = N !

Proof

Step Hyp Ref Expression
1 nn0fz0 ⊢ N ∈ ℕ 0 ↔ N ∈ 0 … N
2 fallfacval4 ⊢ N ∈ 0 … N → N N _ = N ! N − N !
3 1 2 sylbi ⊢ N ∈ ℕ 0 → N N _ = N ! N − N !
4 nn0cn ⊢ N ∈ ℕ 0 → N ∈ ℂ
5 4 subidd ⊢ N ∈ ℕ 0 → N − N = 0
6 5 fveq2d ⊢ N ∈ ℕ 0 → N − N ! = 0 !
7 fac0 ⊢ 0 ! = 1
8 6 7 eqtrdi ⊢ N ∈ ℕ 0 → N − N ! = 1
9 8 oveq2d ⊢ N ∈ ℕ 0 → N ! N − N ! = N ! 1
10 faccl ⊢ N ∈ ℕ 0 → N ! ∈ ℕ
11 10 nncnd ⊢ N ∈ ℕ 0 → N ! ∈ ℂ
12 11 div1d ⊢ N ∈ ℕ 0 → N ! 1 = N !
13 3 9 12 3eqtrd ⊢ N ∈ ℕ 0 → N N _ = N !