Metamath Proof Explorer


Theorem fcoconst

Description: Composition with a constant function. (Contributed by Stefan O'Rear, 11-Mar-2015)

Ref Expression
Assertion fcoconst F Fn X Y X F I × Y = I × F Y

Proof

Step Hyp Ref Expression
1 simplr F Fn X Y X x I Y X
2 fconstmpt I × Y = x I Y
3 2 a1i F Fn X Y X I × Y = x I Y
4 dffn2 F Fn X F : X V
5 4 birani F Fn X Y X F : X V
6 5 feqmptd F Fn X Y X F = y X F y
7 fveq2 y = Y F y = F Y
8 1 3 6 7 fmptco F Fn X Y X F I × Y = x I F Y
9 fconstmpt I × F Y = x I F Y
10 8 9 eqtr4di F Fn X Y X F I × Y = I × F Y