Metamath Proof Explorer


Theorem fconst2g

Description: A constant function expressed as a Cartesian product. (Contributed by NM, 27-Nov-2007)

Ref Expression
Assertion fconst2g ⊢ B ∈ C → F : A ⟶ B ↔ F = A × B

Proof

Step Hyp Ref Expression
1 fvconst ⊢ F : A ⟶ B ∧ x ∈ A → F ⁡ x = B
2 1 adantlr ⊢ F : A ⟶ B ∧ B ∈ C ∧ x ∈ A → F ⁡ x = B
3 fvconst2g ⊢ B ∈ C ∧ x ∈ A → A × B ⁡ x = B
4 3 adantll ⊢ F : A ⟶ B ∧ B ∈ C ∧ x ∈ A → A × B ⁡ x = B
5 2 4 eqtr4d ⊢ F : A ⟶ B ∧ B ∈ C ∧ x ∈ A → F ⁡ x = A × B ⁡ x
6 5 ralrimiva ⊢ F : A ⟶ B ∧ B ∈ C → ∀ x ∈ A F ⁡ x = A × B ⁡ x
7 ffn ⊢ F : A ⟶ B → F Fn A
8 fnconstg ⊢ B ∈ C → A × B Fn A
9 eqfnfv ⊢ F Fn A ∧ A × B Fn A → F = A × B ↔ ∀ x ∈ A F ⁡ x = A × B ⁡ x
10 7 8 9 syl2an ⊢ F : A ⟶ B ∧ B ∈ C → F = A × B ↔ ∀ x ∈ A F ⁡ x = A × B ⁡ x
11 6 10 mpbird ⊢ F : A ⟶ B ∧ B ∈ C → F = A × B
12 11 expcom ⊢ B ∈ C → F : A ⟶ B → F = A × B
13 fconstg ⊢ B ∈ C → A × B : A ⟶ B
14 feq1 ⊢ F = A × B → F : A ⟶ B ↔ A × B : A ⟶ B
15 13 14 syl5ibrcom ⊢ B ∈ C → F = A × B → F : A ⟶ B
16 12 15 impbid ⊢ B ∈ C → F : A ⟶ B ↔ F = A × B