Metamath Proof Explorer


Theorem fdivval

Description: The quotient of two functions into the complex numbers. (Contributed by AV, 15-May-2020)

Ref Expression
Assertion fdivval ⊢ F ∈ V ∧ G ∈ W → F / f G = F ÷ f G ↾ supp 0 ⁡ G

Proof

Step Hyp Ref Expression
1 df-fdiv ⊢ / f = f ∈ V , g ∈ V ⟼ f ÷ f g ↾ supp 0 ⁡ g
2 1 a1i ⊢ F ∈ V ∧ G ∈ W → / f = f ∈ V , g ∈ V ⟼ f ÷ f g ↾ supp 0 ⁡ g
3 oveq12 ⊢ f = F ∧ g = G → f ÷ f g = F ÷ f G
4 oveq1 ⊢ g = G → g supp 0 = G supp 0
5 4 adantl ⊢ f = F ∧ g = G → g supp 0 = G supp 0
6 3 5 reseq12d ⊢ f = F ∧ g = G → f ÷ f g ↾ supp 0 ⁡ g = F ÷ f G ↾ supp 0 ⁡ G
7 6 adantl ⊢ F ∈ V ∧ G ∈ W ∧ f = F ∧ g = G → f ÷ f g ↾ supp 0 ⁡ g = F ÷ f G ↾ supp 0 ⁡ G
8 elex ⊢ F ∈ V → F ∈ V
9 8 adantr ⊢ F ∈ V ∧ G ∈ W → F ∈ V
10 elex ⊢ G ∈ W → G ∈ V
11 10 adantl ⊢ F ∈ V ∧ G ∈ W → G ∈ V
12 funmpt ⊢ Fun ⁡ x ∈ dom ⁡ F ∩ dom ⁡ G ⟼ F ⁡ x G ⁡ x
13 offval3 ⊢ F ∈ V ∧ G ∈ W → F ÷ f G = x ∈ dom ⁡ F ∩ dom ⁡ G ⟼ F ⁡ x G ⁡ x
14 13 funeqd ⊢ F ∈ V ∧ G ∈ W → Fun ⁡ F ÷ f G ↔ Fun ⁡ x ∈ dom ⁡ F ∩ dom ⁡ G ⟼ F ⁡ x G ⁡ x
15 12 14 mpbiri ⊢ F ∈ V ∧ G ∈ W → Fun ⁡ F ÷ f G
16 ovex ⊢ G supp 0 ∈ V
17 resfunexg ⊢ Fun ⁡ F ÷ f G ∧ G supp 0 ∈ V → F ÷ f G ↾ supp 0 ⁡ G ∈ V
18 15 16 17 sylancl ⊢ F ∈ V ∧ G ∈ W → F ÷ f G ↾ supp 0 ⁡ G ∈ V
19 2 7 9 11 18 ovmpod ⊢ F ∈ V ∧ G ∈ W → F / f G = F ÷ f G ↾ supp 0 ⁡ G