Metamath Proof Explorer


Theorem offval3

Description: General value of ( F oF R G ) with no assumptions on functionality of F and G . (Contributed by Stefan O'Rear, 24-Jan-2015)

Ref Expression
Assertion offval3 ⊢ F ∈ V ∧ G ∈ W → F R f G = x ∈ dom ⁡ F ∩ dom ⁡ G ⟼ F ⁡ x R G ⁡ x

Proof

Step Hyp Ref Expression
1 elex ⊢ F ∈ V → F ∈ V
2 1 adantr ⊢ F ∈ V ∧ G ∈ W → F ∈ V
3 elex ⊢ G ∈ W → G ∈ V
4 3 adantl ⊢ F ∈ V ∧ G ∈ W → G ∈ V
5 dmexg ⊢ F ∈ V → dom ⁡ F ∈ V
6 inex1g ⊢ dom ⁡ F ∈ V → dom ⁡ F ∩ dom ⁡ G ∈ V
7 mptexg ⊢ dom ⁡ F ∩ dom ⁡ G ∈ V → x ∈ dom ⁡ F ∩ dom ⁡ G ⟼ F ⁡ x R G ⁡ x ∈ V
8 5 6 7 3syl ⊢ F ∈ V → x ∈ dom ⁡ F ∩ dom ⁡ G ⟼ F ⁡ x R G ⁡ x ∈ V
9 8 adantr ⊢ F ∈ V ∧ G ∈ W → x ∈ dom ⁡ F ∩ dom ⁡ G ⟼ F ⁡ x R G ⁡ x ∈ V
10 dmeq ⊢ a = F → dom ⁡ a = dom ⁡ F
11 dmeq ⊢ b = G → dom ⁡ b = dom ⁡ G
12 10 11 ineqan12d ⊢ a = F ∧ b = G → dom ⁡ a ∩ dom ⁡ b = dom ⁡ F ∩ dom ⁡ G
13 fveq1 ⊢ a = F → a ⁡ x = F ⁡ x
14 fveq1 ⊢ b = G → b ⁡ x = G ⁡ x
15 13 14 oveqan12d ⊢ a = F ∧ b = G → a ⁡ x R b ⁡ x = F ⁡ x R G ⁡ x
16 12 15 mpteq12dv ⊢ a = F ∧ b = G → x ∈ dom ⁡ a ∩ dom ⁡ b ⟼ a ⁡ x R b ⁡ x = x ∈ dom ⁡ F ∩ dom ⁡ G ⟼ F ⁡ x R G ⁡ x
17 df-of ⊢ ∘ f ⁡ R = a ∈ V , b ∈ V ⟼ x ∈ dom ⁡ a ∩ dom ⁡ b ⟼ a ⁡ x R b ⁡ x
18 16 17 ovmpoga ⊢ F ∈ V ∧ G ∈ V ∧ x ∈ dom ⁡ F ∩ dom ⁡ G ⟼ F ⁡ x R G ⁡ x ∈ V → F R f G = x ∈ dom ⁡ F ∩ dom ⁡ G ⟼ F ⁡ x R G ⁡ x
19 2 4 9 18 syl3anc ⊢ F ∈ V ∧ G ∈ W → F R f G = x ∈ dom ⁡ F ∩ dom ⁡ G ⟼ F ⁡ x R G ⁡ x