Metamath Proof Explorer


Theorem fpwwelem

Description: Lemma for fpwwe . (Contributed by Mario Carneiro, 15-May-2015) (Revised by AV, 20-Jul-2024)

Ref Expression
Hypotheses fpwwe.1 ⊢ W = x r | x ⊆ A ∧ r ⊆ x × x ∧ r We x ∧ ∀ y ∈ x F ⁡ r -1 y = y
fpwwe.2 ⊢ φ → A ∈ V
Assertion fpwwelem ⊢ φ → X W R ↔ X ⊆ A ∧ R ⊆ X × X ∧ R We X ∧ ∀ y ∈ X F ⁡ R -1 y = y

Proof

Step Hyp Ref Expression
1 fpwwe.1 ⊢ W = x r | x ⊆ A ∧ r ⊆ x × x ∧ r We x ∧ ∀ y ∈ x F ⁡ r -1 y = y
2 fpwwe.2 ⊢ φ → A ∈ V
3 1 relopabiv ⊢ Rel ⁡ W
4 3 a1i ⊢ φ → Rel ⁡ W
5 brrelex12 ⊢ Rel ⁡ W ∧ X W R → X ∈ V ∧ R ∈ V
6 4 5 sylan ⊢ φ ∧ X W R → X ∈ V ∧ R ∈ V
7 2 adantr ⊢ φ ∧ X ⊆ A ∧ R ⊆ X × X ∧ R We X ∧ ∀ y ∈ X F ⁡ R -1 y = y → A ∈ V
8 simprll ⊢ φ ∧ X ⊆ A ∧ R ⊆ X × X ∧ R We X ∧ ∀ y ∈ X F ⁡ R -1 y = y → X ⊆ A
9 7 8 ssexd ⊢ φ ∧ X ⊆ A ∧ R ⊆ X × X ∧ R We X ∧ ∀ y ∈ X F ⁡ R -1 y = y → X ∈ V
10 9 9 xpexd ⊢ φ ∧ X ⊆ A ∧ R ⊆ X × X ∧ R We X ∧ ∀ y ∈ X F ⁡ R -1 y = y → X × X ∈ V
11 simprlr ⊢ φ ∧ X ⊆ A ∧ R ⊆ X × X ∧ R We X ∧ ∀ y ∈ X F ⁡ R -1 y = y → R ⊆ X × X
12 10 11 ssexd ⊢ φ ∧ X ⊆ A ∧ R ⊆ X × X ∧ R We X ∧ ∀ y ∈ X F ⁡ R -1 y = y → R ∈ V
13 9 12 jca ⊢ φ ∧ X ⊆ A ∧ R ⊆ X × X ∧ R We X ∧ ∀ y ∈ X F ⁡ R -1 y = y → X ∈ V ∧ R ∈ V
14 simpl ⊢ x = X ∧ r = R → x = X
15 14 sseq1d ⊢ x = X ∧ r = R → x ⊆ A ↔ X ⊆ A
16 simpr ⊢ x = X ∧ r = R → r = R
17 14 sqxpeqd ⊢ x = X ∧ r = R → x × x = X × X
18 16 17 sseq12d ⊢ x = X ∧ r = R → r ⊆ x × x ↔ R ⊆ X × X
19 15 18 anbi12d ⊢ x = X ∧ r = R → x ⊆ A ∧ r ⊆ x × x ↔ X ⊆ A ∧ R ⊆ X × X
20 16 14 weeq12d ⊢ x = X ∧ r = R → r We x ↔ R We X
21 16 cnveqd ⊢ x = X ∧ r = R → r -1 = R -1
22 21 imaeq1d ⊢ x = X ∧ r = R → r -1 y = R -1 y
23 22 fveqeq2d ⊢ x = X ∧ r = R → F ⁡ r -1 y = y ↔ F ⁡ R -1 y = y
24 14 23 raleqbidv ⊢ x = X ∧ r = R → ∀ y ∈ x F ⁡ r -1 y = y ↔ ∀ y ∈ X F ⁡ R -1 y = y
25 20 24 anbi12d ⊢ x = X ∧ r = R → r We x ∧ ∀ y ∈ x F ⁡ r -1 y = y ↔ R We X ∧ ∀ y ∈ X F ⁡ R -1 y = y
26 19 25 anbi12d ⊢ x = X ∧ r = R → x ⊆ A ∧ r ⊆ x × x ∧ r We x ∧ ∀ y ∈ x F ⁡ r -1 y = y ↔ X ⊆ A ∧ R ⊆ X × X ∧ R We X ∧ ∀ y ∈ X F ⁡ R -1 y = y
27 26 1 brabga ⊢ X ∈ V ∧ R ∈ V → X W R ↔ X ⊆ A ∧ R ⊆ X × X ∧ R We X ∧ ∀ y ∈ X F ⁡ R -1 y = y
28 6 13 27 pm5.21nd ⊢ φ → X W R ↔ X ⊆ A ∧ R ⊆ X × X ∧ R We X ∧ ∀ y ∈ X F ⁡ R -1 y = y