Metamath Proof Explorer


Theorem fsum2d

Description: Write a double sum as a sum over a two-dimensional region. Note that B ( j ) is a function of j . (Contributed by Mario Carneiro, 27-Apr-2014)

Ref Expression
Hypotheses fsum2d.1 ⊢ z = j k → D = C
fsum2d.2 ⊢ φ → A ∈ Fin
fsum2d.3 ⊢ φ ∧ j ∈ A → B ∈ Fin
fsum2d.4 ⊢ φ ∧ j ∈ A ∧ k ∈ B → C ∈ ℂ
Assertion fsum2d ⊢ φ → ∑ j ∈ A ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ A j × B D

Proof

Step Hyp Ref Expression
1 fsum2d.1 ⊢ z = j k → D = C
2 fsum2d.2 ⊢ φ → A ∈ Fin
3 fsum2d.3 ⊢ φ ∧ j ∈ A → B ∈ Fin
4 fsum2d.4 ⊢ φ ∧ j ∈ A ∧ k ∈ B → C ∈ ℂ
5 ssid ⊢ A ⊆ A
6 sseq1 ⊢ w = ∅ → w ⊆ A ↔ ∅ ⊆ A
7 sumeq1 ⊢ w = ∅ → ∑ j ∈ w ∑ k ∈ B C = ∑ j ∈ ∅ ∑ k ∈ B C
8 iuneq1 ⊢ w = ∅ → ⋃ j ∈ w j × B = ⋃ j ∈ ∅ j × B
9 8 sumeq1d ⊢ w = ∅ → ∑ z ∈ ⋃ j ∈ w j × B D = ∑ z ∈ ⋃ j ∈ ∅ j × B D
10 7 9 eqeq12d ⊢ w = ∅ → ∑ j ∈ w ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ w j × B D ↔ ∑ j ∈ ∅ ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ ∅ j × B D
11 6 10 imbi12d ⊢ w = ∅ → w ⊆ A → ∑ j ∈ w ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ w j × B D ↔ ∅ ⊆ A → ∑ j ∈ ∅ ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ ∅ j × B D
12 11 imbi2d ⊢ w = ∅ → φ → w ⊆ A → ∑ j ∈ w ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ w j × B D ↔ φ → ∅ ⊆ A → ∑ j ∈ ∅ ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ ∅ j × B D
13 sseq1 ⊢ w = x → w ⊆ A ↔ x ⊆ A
14 sumeq1 ⊢ w = x → ∑ j ∈ w ∑ k ∈ B C = ∑ j ∈ x ∑ k ∈ B C
15 iuneq1 ⊢ w = x → ⋃ j ∈ w j × B = ⋃ j ∈ x j × B
16 15 sumeq1d ⊢ w = x → ∑ z ∈ ⋃ j ∈ w j × B D = ∑ z ∈ ⋃ j ∈ x j × B D
17 14 16 eqeq12d ⊢ w = x → ∑ j ∈ w ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ w j × B D ↔ ∑ j ∈ x ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x j × B D
18 13 17 imbi12d ⊢ w = x → w ⊆ A → ∑ j ∈ w ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ w j × B D ↔ x ⊆ A → ∑ j ∈ x ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x j × B D
19 18 imbi2d ⊢ w = x → φ → w ⊆ A → ∑ j ∈ w ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ w j × B D ↔ φ → x ⊆ A → ∑ j ∈ x ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x j × B D
20 sseq1 ⊢ w = x ∪ y → w ⊆ A ↔ x ∪ y ⊆ A
21 sumeq1 ⊢ w = x ∪ y → ∑ j ∈ w ∑ k ∈ B C = ∑ j ∈ x ∪ y ∑ k ∈ B C
22 iuneq1 ⊢ w = x ∪ y → ⋃ j ∈ w j × B = ⋃ j ∈ x ∪ y j × B
23 22 sumeq1d ⊢ w = x ∪ y → ∑ z ∈ ⋃ j ∈ w j × B D = ∑ z ∈ ⋃ j ∈ x ∪ y j × B D
24 21 23 eqeq12d ⊢ w = x ∪ y → ∑ j ∈ w ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ w j × B D ↔ ∑ j ∈ x ∪ y ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x ∪ y j × B D
25 20 24 imbi12d ⊢ w = x ∪ y → w ⊆ A → ∑ j ∈ w ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ w j × B D ↔ x ∪ y ⊆ A → ∑ j ∈ x ∪ y ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x ∪ y j × B D
26 25 imbi2d ⊢ w = x ∪ y → φ → w ⊆ A → ∑ j ∈ w ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ w j × B D ↔ φ → x ∪ y ⊆ A → ∑ j ∈ x ∪ y ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x ∪ y j × B D
27 sseq1 ⊢ w = A → w ⊆ A ↔ A ⊆ A
28 sumeq1 ⊢ w = A → ∑ j ∈ w ∑ k ∈ B C = ∑ j ∈ A ∑ k ∈ B C
29 iuneq1 ⊢ w = A → ⋃ j ∈ w j × B = ⋃ j ∈ A j × B
30 29 sumeq1d ⊢ w = A → ∑ z ∈ ⋃ j ∈ w j × B D = ∑ z ∈ ⋃ j ∈ A j × B D
31 28 30 eqeq12d ⊢ w = A → ∑ j ∈ w ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ w j × B D ↔ ∑ j ∈ A ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ A j × B D
32 27 31 imbi12d ⊢ w = A → w ⊆ A → ∑ j ∈ w ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ w j × B D ↔ A ⊆ A → ∑ j ∈ A ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ A j × B D
33 32 imbi2d ⊢ w = A → φ → w ⊆ A → ∑ j ∈ w ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ w j × B D ↔ φ → A ⊆ A → ∑ j ∈ A ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ A j × B D
34 sum0 ⊢ ∑ z ∈ ∅ D = 0
35 0iun ⊢ ⋃ j ∈ ∅ j × B = ∅
36 35 sumeq1i ⊢ ∑ z ∈ ⋃ j ∈ ∅ j × B D = ∑ z ∈ ∅ D
37 sum0 ⊢ ∑ j ∈ ∅ ∑ k ∈ B C = 0
38 34 36 37 3eqtr4ri ⊢ ∑ j ∈ ∅ ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ ∅ j × B D
39 38 2a1i ⊢ φ → ∅ ⊆ A → ∑ j ∈ ∅ ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ ∅ j × B D
40 ssun1 ⊢ x ⊆ x ∪ y
41 sstr ⊢ x ⊆ x ∪ y ∧ x ∪ y ⊆ A → x ⊆ A
42 40 41 mpan ⊢ x ∪ y ⊆ A → x ⊆ A
43 42 imim1i ⊢ x ⊆ A → ∑ j ∈ x ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x j × B D → x ∪ y ⊆ A → ∑ j ∈ x ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x j × B D
44 simpll ⊢ φ ∧ ¬ y ∈ x ∧ x ∪ y ⊆ A → φ
45 44 2 syl ⊢ φ ∧ ¬ y ∈ x ∧ x ∪ y ⊆ A → A ∈ Fin
46 44 3 sylan ⊢ φ ∧ ¬ y ∈ x ∧ x ∪ y ⊆ A ∧ j ∈ A → B ∈ Fin
47 44 4 sylan ⊢ φ ∧ ¬ y ∈ x ∧ x ∪ y ⊆ A ∧ j ∈ A ∧ k ∈ B → C ∈ ℂ
48 simplr ⊢ φ ∧ ¬ y ∈ x ∧ x ∪ y ⊆ A → ¬ y ∈ x
49 simpr ⊢ φ ∧ ¬ y ∈ x ∧ x ∪ y ⊆ A → x ∪ y ⊆ A
50 biid ⊢ ∑ j ∈ x ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x j × B D ↔ ∑ j ∈ x ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x j × B D
51 1 45 46 47 48 49 50 fsum2dlem ⊢ φ ∧ ¬ y ∈ x ∧ x ∪ y ⊆ A ∧ ∑ j ∈ x ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x j × B D → ∑ j ∈ x ∪ y ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x ∪ y j × B D
52 51 exp31 ⊢ φ ∧ ¬ y ∈ x → x ∪ y ⊆ A → ∑ j ∈ x ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x j × B D → ∑ j ∈ x ∪ y ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x ∪ y j × B D
53 52 a2d ⊢ φ ∧ ¬ y ∈ x → x ∪ y ⊆ A → ∑ j ∈ x ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x j × B D → x ∪ y ⊆ A → ∑ j ∈ x ∪ y ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x ∪ y j × B D
54 43 53 syl5 ⊢ φ ∧ ¬ y ∈ x → x ⊆ A → ∑ j ∈ x ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x j × B D → x ∪ y ⊆ A → ∑ j ∈ x ∪ y ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x ∪ y j × B D
55 54 expcom ⊢ ¬ y ∈ x → φ → x ⊆ A → ∑ j ∈ x ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x j × B D → x ∪ y ⊆ A → ∑ j ∈ x ∪ y ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x ∪ y j × B D
56 55 a2d ⊢ ¬ y ∈ x → φ → x ⊆ A → ∑ j ∈ x ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x j × B D → φ → x ∪ y ⊆ A → ∑ j ∈ x ∪ y ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x ∪ y j × B D
57 56 adantl ⊢ x ∈ Fin ∧ ¬ y ∈ x → φ → x ⊆ A → ∑ j ∈ x ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x j × B D → φ → x ∪ y ⊆ A → ∑ j ∈ x ∪ y ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ x ∪ y j × B D
58 12 19 26 33 39 57 findcard2s ⊢ A ∈ Fin → φ → A ⊆ A → ∑ j ∈ A ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ A j × B D
59 2 58 mpcom ⊢ φ → A ⊆ A → ∑ j ∈ A ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ A j × B D
60 5 59 mpi ⊢ φ → ∑ j ∈ A ∑ k ∈ B C = ∑ z ∈ ⋃ j ∈ A j × B D