Metamath Proof Explorer


Theorem funpartfv

Description: The function value of the functional part is identical to the original functional value. (Contributed by Scott Fenton, 17-Apr-2014) (Revised by Mario Carneiro, 19-Apr-2014)

Ref Expression
Assertion funpartfv ⊢ 𝖥𝗎𝗇𝖯𝖺𝗋𝗍 F ⁡ A = F ⁡ A

Proof

Step Hyp Ref Expression
1 df-funpart ⊢ 𝖥𝗎𝗇𝖯𝖺𝗋𝗍 F = F ↾ dom ⁡ 𝖨𝗆𝖺𝗀𝖾 F ∘ 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇 ∩ V × 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇𝗌
2 1 fveq1i ⊢ 𝖥𝗎𝗇𝖯𝖺𝗋𝗍 F ⁡ A = F ↾ dom ⁡ 𝖨𝗆𝖺𝗀𝖾 F ∘ 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇 ∩ V × 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇𝗌 ⁡ A
3 fvres ⊢ A ∈ dom ⁡ 𝖨𝗆𝖺𝗀𝖾 F ∘ 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇 ∩ V × 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇𝗌 → F ↾ dom ⁡ 𝖨𝗆𝖺𝗀𝖾 F ∘ 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇 ∩ V × 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇𝗌 ⁡ A = F ⁡ A
4 nfvres ⊢ ¬ A ∈ dom ⁡ 𝖨𝗆𝖺𝗀𝖾 F ∘ 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇 ∩ V × 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇𝗌 → F ↾ dom ⁡ 𝖨𝗆𝖺𝗀𝖾 F ∘ 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇 ∩ V × 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇𝗌 ⁡ A = ∅
5 funpartlem ⊢ A ∈ dom ⁡ 𝖨𝗆𝖺𝗀𝖾 F ∘ 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇 ∩ V × 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇𝗌 ↔ ∃ x F A = x
6 eusn ⊢ ∃! x x ∈ F A ↔ ∃ x F A = x
7 5 6 bitr4i ⊢ A ∈ dom ⁡ 𝖨𝗆𝖺𝗀𝖾 F ∘ 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇 ∩ V × 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇𝗌 ↔ ∃! x x ∈ F A
8 elimasng ⊢ A ∈ V ∧ x ∈ V → x ∈ F A ↔ A x ∈ F
9 8 elvd ⊢ A ∈ V → x ∈ F A ↔ A x ∈ F
10 df-br ⊢ A F x ↔ A x ∈ F
11 9 10 bitr4di ⊢ A ∈ V → x ∈ F A ↔ A F x
12 11 eubidv ⊢ A ∈ V → ∃! x x ∈ F A ↔ ∃! x A F x
13 7 12 bitrid ⊢ A ∈ V → A ∈ dom ⁡ 𝖨𝗆𝖺𝗀𝖾 F ∘ 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇 ∩ V × 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇𝗌 ↔ ∃! x A F x
14 13 notbid ⊢ A ∈ V → ¬ A ∈ dom ⁡ 𝖨𝗆𝖺𝗀𝖾 F ∘ 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇 ∩ V × 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇𝗌 ↔ ¬ ∃! x A F x
15 tz6.12-2 ⊢ ¬ ∃! x A F x → F ⁡ A = ∅
16 14 15 biimtrdi ⊢ A ∈ V → ¬ A ∈ dom ⁡ 𝖨𝗆𝖺𝗀𝖾 F ∘ 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇 ∩ V × 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇𝗌 → F ⁡ A = ∅
17 fvprc ⊢ ¬ A ∈ V → F ⁡ A = ∅
18 17 a1d ⊢ ¬ A ∈ V → ¬ A ∈ dom ⁡ 𝖨𝗆𝖺𝗀𝖾 F ∘ 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇 ∩ V × 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇𝗌 → F ⁡ A = ∅
19 16 18 pm2.61i ⊢ ¬ A ∈ dom ⁡ 𝖨𝗆𝖺𝗀𝖾 F ∘ 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇 ∩ V × 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇𝗌 → F ⁡ A = ∅
20 4 19 eqtr4d ⊢ ¬ A ∈ dom ⁡ 𝖨𝗆𝖺𝗀𝖾 F ∘ 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇 ∩ V × 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇𝗌 → F ↾ dom ⁡ 𝖨𝗆𝖺𝗀𝖾 F ∘ 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇 ∩ V × 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇𝗌 ⁡ A = F ⁡ A
21 3 20 pm2.61i ⊢ F ↾ dom ⁡ 𝖨𝗆𝖺𝗀𝖾 F ∘ 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇 ∩ V × 𝖲𝗂𝗇𝗀𝗅𝖾𝗍𝗈𝗇𝗌 ⁡ A = F ⁡ A
22 2 21 eqtri ⊢ 𝖥𝗎𝗇𝖯𝖺𝗋𝗍 F ⁡ A = F ⁡ A