Metamath Proof Explorer


Theorem ghmlin

Description: A homomorphism of groups is linear. (Contributed by Stefan O'Rear, 31-Dec-2014)

Ref Expression
Hypotheses ghmlin.x ⊢ X = Base S
ghmlin.a ⊢ + ˙ = + S
ghmlin.b ⊢ ⨣ ˙ = + T
Assertion ghmlin ⊢ F ∈ S GrpHom T ∧ U ∈ X ∧ V ∈ X → F ⁡ U + ˙ V = F ⁡ U ⨣ ˙ F ⁡ V

Proof

Step Hyp Ref Expression
1 ghmlin.x ⊢ X = Base S
2 ghmlin.a ⊢ + ˙ = + S
3 ghmlin.b ⊢ ⨣ ˙ = + T
4 eqid ⊢ Base T = Base T
5 1 4 2 3 isghm ⊢ F ∈ S GrpHom T ↔ S ∈ Grp ∧ T ∈ Grp ∧ F : X ⟶ Base T ∧ ∀ a ∈ X ∀ b ∈ X F ⁡ a + ˙ b = F ⁡ a ⨣ ˙ F ⁡ b
6 5 simprbi ⊢ F ∈ S GrpHom T → F : X ⟶ Base T ∧ ∀ a ∈ X ∀ b ∈ X F ⁡ a + ˙ b = F ⁡ a ⨣ ˙ F ⁡ b
7 6 simprd ⊢ F ∈ S GrpHom T → ∀ a ∈ X ∀ b ∈ X F ⁡ a + ˙ b = F ⁡ a ⨣ ˙ F ⁡ b
8 fvoveq1 ⊢ a = U → F ⁡ a + ˙ b = F ⁡ U + ˙ b
9 fveq2 ⊢ a = U → F ⁡ a = F ⁡ U
10 9 oveq1d ⊢ a = U → F ⁡ a ⨣ ˙ F ⁡ b = F ⁡ U ⨣ ˙ F ⁡ b
11 8 10 eqeq12d ⊢ a = U → F ⁡ a + ˙ b = F ⁡ a ⨣ ˙ F ⁡ b ↔ F ⁡ U + ˙ b = F ⁡ U ⨣ ˙ F ⁡ b
12 oveq2 ⊢ b = V → U + ˙ b = U + ˙ V
13 12 fveq2d ⊢ b = V → F ⁡ U + ˙ b = F ⁡ U + ˙ V
14 fveq2 ⊢ b = V → F ⁡ b = F ⁡ V
15 14 oveq2d ⊢ b = V → F ⁡ U ⨣ ˙ F ⁡ b = F ⁡ U ⨣ ˙ F ⁡ V
16 13 15 eqeq12d ⊢ b = V → F ⁡ U + ˙ b = F ⁡ U ⨣ ˙ F ⁡ b ↔ F ⁡ U + ˙ V = F ⁡ U ⨣ ˙ F ⁡ V
17 11 16 rspc2v ⊢ U ∈ X ∧ V ∈ X → ∀ a ∈ X ∀ b ∈ X F ⁡ a + ˙ b = F ⁡ a ⨣ ˙ F ⁡ b → F ⁡ U + ˙ V = F ⁡ U ⨣ ˙ F ⁡ V
18 7 17 mpan9 ⊢ F ∈ S GrpHom T ∧ U ∈ X ∧ V ∈ X → F ⁡ U + ˙ V = F ⁡ U ⨣ ˙ F ⁡ V
19 18 3impb ⊢ F ∈ S GrpHom T ∧ U ∈ X ∧ V ∈ X → F ⁡ U + ˙ V = F ⁡ U ⨣ ˙ F ⁡ V