Metamath Proof Explorer


Theorem grplrinv

Description: In a group, every member has a left and right inverse. (Contributed by AV, 1-Sep-2021)

Ref Expression
Hypotheses grplrinv.b ⊢ B = Base G
grplrinv.p ⊢ + ˙ = + G
grplrinv.i ⊢ 0 ˙ = 0 G
Assertion grplrinv ⊢ G ∈ Grp → ∀ x ∈ B ∃ y ∈ B y + ˙ x = 0 ˙ ∧ x + ˙ y = 0 ˙

Proof

Step Hyp Ref Expression
1 grplrinv.b ⊢ B = Base G
2 grplrinv.p ⊢ + ˙ = + G
3 grplrinv.i ⊢ 0 ˙ = 0 G
4 eqid ⊢ inv g ⁡ G = inv g ⁡ G
5 1 4 grpinvcl ⊢ G ∈ Grp ∧ x ∈ B → inv g ⁡ G ⁡ x ∈ B
6 oveq1 ⊢ y = inv g ⁡ G ⁡ x → y + ˙ x = inv g ⁡ G ⁡ x + ˙ x
7 6 eqeq1d ⊢ y = inv g ⁡ G ⁡ x → y + ˙ x = 0 ˙ ↔ inv g ⁡ G ⁡ x + ˙ x = 0 ˙
8 oveq2 ⊢ y = inv g ⁡ G ⁡ x → x + ˙ y = x + ˙ inv g ⁡ G ⁡ x
9 8 eqeq1d ⊢ y = inv g ⁡ G ⁡ x → x + ˙ y = 0 ˙ ↔ x + ˙ inv g ⁡ G ⁡ x = 0 ˙
10 7 9 anbi12d ⊢ y = inv g ⁡ G ⁡ x → y + ˙ x = 0 ˙ ∧ x + ˙ y = 0 ˙ ↔ inv g ⁡ G ⁡ x + ˙ x = 0 ˙ ∧ x + ˙ inv g ⁡ G ⁡ x = 0 ˙
11 10 adantl ⊢ G ∈ Grp ∧ x ∈ B ∧ y = inv g ⁡ G ⁡ x → y + ˙ x = 0 ˙ ∧ x + ˙ y = 0 ˙ ↔ inv g ⁡ G ⁡ x + ˙ x = 0 ˙ ∧ x + ˙ inv g ⁡ G ⁡ x = 0 ˙
12 1 2 3 4 grplinv ⊢ G ∈ Grp ∧ x ∈ B → inv g ⁡ G ⁡ x + ˙ x = 0 ˙
13 1 2 3 4 grprinv ⊢ G ∈ Grp ∧ x ∈ B → x + ˙ inv g ⁡ G ⁡ x = 0 ˙
14 12 13 jca ⊢ G ∈ Grp ∧ x ∈ B → inv g ⁡ G ⁡ x + ˙ x = 0 ˙ ∧ x + ˙ inv g ⁡ G ⁡ x = 0 ˙
15 5 11 14 rspcedvd ⊢ G ∈ Grp ∧ x ∈ B → ∃ y ∈ B y + ˙ x = 0 ˙ ∧ x + ˙ y = 0 ˙
16 15 ralrimiva ⊢ G ∈ Grp → ∀ x ∈ B ∃ y ∈ B y + ˙ x = 0 ˙ ∧ x + ˙ y = 0 ˙