Metamath Proof Explorer


Theorem grplinv

Description: The left inverse of a group element. (Contributed by NM, 24-Aug-2011) (Revised by Mario Carneiro, 6-Jan-2015)

Ref Expression
Hypotheses grpinv.b B=BaseG
grpinv.p +˙=+G
grpinv.u 0˙=0G
grpinv.n N=invgG
Assertion grplinv GGrpXBNX+˙X=0˙

Proof

Step Hyp Ref Expression
1 grpinv.b B=BaseG
2 grpinv.p +˙=+G
3 grpinv.u 0˙=0G
4 grpinv.n N=invgG
5 1 2 3 4 grpinvval XBNX=ιyB|y+˙X=0˙
6 5 adantl GGrpXBNX=ιyB|y+˙X=0˙
7 1 2 3 grpinveu GGrpXB∃!yBy+˙X=0˙
8 riotacl2 ∃!yBy+˙X=0˙ιyB|y+˙X=0˙yB|y+˙X=0˙
9 7 8 syl GGrpXBιyB|y+˙X=0˙yB|y+˙X=0˙
10 6 9 eqeltrd GGrpXBNXyB|y+˙X=0˙
11 oveq1 y=NXy+˙X=NX+˙X
12 11 eqeq1d y=NXy+˙X=0˙NX+˙X=0˙
13 12 elrab NXyB|y+˙X=0˙NXBNX+˙X=0˙
14 13 simprbi NXyB|y+˙X=0˙NX+˙X=0˙
15 10 14 syl GGrpXBNX+˙X=0˙