Metamath Proof Explorer


Theorem gsummptmhm

Description: Apply a group homomorphism to a group sum expressed with a mapping. (Contributed by Thierry Arnoux, 7-Sep-2018) (Revised by AV, 8-Sep-2019)

Ref Expression
Hypotheses gsummptmhm.b ⊢ B = Base G
gsummptmhm.z ⊢ 0 ˙ = 0 G
gsummptmhm.g ⊢ φ → G ∈ CMnd
gsummptmhm.h ⊢ φ → H ∈ Mnd
gsummptmhm.a ⊢ φ → A ∈ V
gsummptmhm.k ⊢ φ → K ∈ G MndHom H
gsummptmhm.c ⊢ φ ∧ x ∈ A → C ∈ B
gsummptmhm.w ⊢ φ → finSupp 0 ˙⁡ x ∈ A ⟼ C
Assertion gsummptmhm ⊢ φ → ∑ H x ∈ A K ⁡ C = K ⁡ ∑ G x ∈ A C

Proof

Step Hyp Ref Expression
1 gsummptmhm.b ⊢ B = Base G
2 gsummptmhm.z ⊢ 0 ˙ = 0 G
3 gsummptmhm.g ⊢ φ → G ∈ CMnd
4 gsummptmhm.h ⊢ φ → H ∈ Mnd
5 gsummptmhm.a ⊢ φ → A ∈ V
6 gsummptmhm.k ⊢ φ → K ∈ G MndHom H
7 gsummptmhm.c ⊢ φ ∧ x ∈ A → C ∈ B
8 gsummptmhm.w ⊢ φ → finSupp 0 ˙⁡ x ∈ A ⟼ C
9 eqidd ⊢ φ → x ∈ A ⟼ C = x ∈ A ⟼ C
10 eqid ⊢ Base H = Base H
11 1 10 mhmf ⊢ K ∈ G MndHom H → K : B ⟶ Base H
12 ffn ⊢ K : B ⟶ Base H → K Fn B
13 6 11 12 3syl ⊢ φ → K Fn B
14 dffn5 ⊢ K Fn B ↔ K = y ∈ B ⟼ K ⁡ y
15 13 14 sylib ⊢ φ → K = y ∈ B ⟼ K ⁡ y
16 fveq2 ⊢ y = C → K ⁡ y = K ⁡ C
17 7 9 15 16 fmptco ⊢ φ → K ∘ x ∈ A ⟼ C = x ∈ A ⟼ K ⁡ C
18 17 oveq2d ⊢ φ → ∑ H K ∘ x ∈ A ⟼ C = ∑ H x ∈ A K ⁡ C
19 7 fmpttd ⊢ φ → x ∈ A ⟼ C : A ⟶ B
20 1 2 3 4 5 6 19 8 gsummhm ⊢ φ → ∑ H K ∘ x ∈ A ⟼ C = K ⁡ ∑ G x ∈ A C
21 18 20 eqtr3d ⊢ φ → ∑ H x ∈ A K ⁡ C = K ⁡ ∑ G x ∈ A C