Metamath Proof Explorer


Theorem gsummulgc2

Description: A finite group sum multiplied by a constant. (Contributed by Thierry Arnoux, 5-Oct-2025)

Ref Expression
Hypotheses gsummulgc1.b ⊢ B = Base M
gsummulgc1.t ⊢ · ˙ = ⋅ M
gsummulgc1.r ⊢ φ → M ∈ Grp
gsummulgc1.a ⊢ φ → A ∈ Fin
gsummulgc1.y ⊢ φ → Y ∈ B
gsummulgc1.x ⊢ φ ∧ k ∈ A → X ∈ ℤ
Assertion gsummulgc2 ⊢ φ → ∑ M k ∈ A X · ˙ Y = ∑ k ∈ A X · ˙ Y

Proof

Step Hyp Ref Expression
1 gsummulgc1.b ⊢ B = Base M
2 gsummulgc1.t ⊢ · ˙ = ⋅ M
3 gsummulgc1.r ⊢ φ → M ∈ Grp
4 gsummulgc1.a ⊢ φ → A ∈ Fin
5 gsummulgc1.y ⊢ φ → Y ∈ B
6 gsummulgc1.x ⊢ φ ∧ k ∈ A → X ∈ ℤ
7 zringbas ⊢ ℤ = Base ℤ ring
8 zring0 ⊢ 0 = 0 ℤ ring
9 zringring ⊢ ℤ ring ∈ Ring
10 ringcmn ⊢ ℤ ring ∈ Ring → ℤ ring ∈ CMnd
11 9 10 mp1i ⊢ φ → ℤ ring ∈ CMnd
12 3 grpmndd ⊢ φ → M ∈ Mnd
13 eqid ⊢ x ∈ ℤ ⟼ x · ˙ Y = x ∈ ℤ ⟼ x · ˙ Y
14 2 13 1 mulgghm2 ⊢ M ∈ Grp ∧ Y ∈ B → x ∈ ℤ ⟼ x · ˙ Y ∈ ℤ ring GrpHom M
15 3 5 14 syl2anc ⊢ φ → x ∈ ℤ ⟼ x · ˙ Y ∈ ℤ ring GrpHom M
16 ghmmhm ⊢ x ∈ ℤ ⟼ x · ˙ Y ∈ ℤ ring GrpHom M → x ∈ ℤ ⟼ x · ˙ Y ∈ ℤ ring MndHom M
17 15 16 syl ⊢ φ → x ∈ ℤ ⟼ x · ˙ Y ∈ ℤ ring MndHom M
18 eqid ⊢ k ∈ A ⟼ X = k ∈ A ⟼ X
19 0zd ⊢ φ → 0 ∈ ℤ
20 18 4 6 19 fsuppmptdm ⊢ φ → finSupp 0 ⁡ k ∈ A ⟼ X
21 oveq1 ⊢ x = X → x · ˙ Y = X · ˙ Y
22 oveq1 ⊢ x = ∑ ℤ ring k ∈ A X → x · ˙ Y = ∑ ℤ ring k ∈ A X · ˙ Y
23 7 8 11 12 4 17 6 20 21 22 gsummhm2 ⊢ φ → ∑ M k ∈ A X · ˙ Y = ∑ ℤ ring k ∈ A X · ˙ Y
24 4 6 gsumzrsum ⊢ φ → ∑ ℤ ring k ∈ A X = ∑ k ∈ A X
25 24 oveq1d ⊢ φ → ∑ ℤ ring k ∈ A X · ˙ Y = ∑ k ∈ A X · ˙ Y
26 23 25 eqtrd ⊢ φ → ∑ M k ∈ A X · ˙ Y = ∑ k ∈ A X · ˙ Y