Metamath Proof Explorer


Theorem hdmap14lem15

Description: Part of proof of part 14 in Baer p. 50 line 3. Convert scalar base of dual to scalar base of vector space. (Contributed by NM, 6-Jun-2015)

Ref Expression
Hypotheses hdmap14lem12.h ⊢ H = LHyp ⁡ K
hdmap14lem12.u ⊢ U = DVecH ⁡ K ⁡ W
hdmap14lem12.v ⊢ V = Base U
hdmap14lem12.t ⊢ · ˙ = ⋅ U
hdmap14lem12.r ⊢ R = Scalar ⁡ U
hdmap14lem12.b ⊢ B = Base R
hdmap14lem12.c ⊢ C = LCDual ⁡ K ⁡ W
hdmap14lem12.e ⊢ ∙ ˙ = ⋅ C
hdmap14lem12.s ⊢ S = HDMap ⁡ K ⁡ W
hdmap14lem12.k ⊢ φ → K ∈ HL ∧ W ∈ H
hdmap14lem12.f ⊢ φ → F ∈ B
Assertion hdmap14lem15 ⊢ φ → ∃! g ∈ B ∀ x ∈ V S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x

Proof

Step Hyp Ref Expression
1 hdmap14lem12.h ⊢ H = LHyp ⁡ K
2 hdmap14lem12.u ⊢ U = DVecH ⁡ K ⁡ W
3 hdmap14lem12.v ⊢ V = Base U
4 hdmap14lem12.t ⊢ · ˙ = ⋅ U
5 hdmap14lem12.r ⊢ R = Scalar ⁡ U
6 hdmap14lem12.b ⊢ B = Base R
7 hdmap14lem12.c ⊢ C = LCDual ⁡ K ⁡ W
8 hdmap14lem12.e ⊢ ∙ ˙ = ⋅ C
9 hdmap14lem12.s ⊢ S = HDMap ⁡ K ⁡ W
10 hdmap14lem12.k ⊢ φ → K ∈ HL ∧ W ∈ H
11 hdmap14lem12.f ⊢ φ → F ∈ B
12 eqid ⊢ Scalar ⁡ C = Scalar ⁡ C
13 eqid ⊢ Base Scalar ⁡ C = Base Scalar ⁡ C
14 1 2 3 4 5 6 7 8 9 10 11 12 13 hdmap14lem14 ⊢ φ → ∃! g ∈ Base Scalar ⁡ C ∀ x ∈ V S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x
15 1 2 5 6 7 12 13 10 lcdsbase ⊢ φ → Base Scalar ⁡ C = B
16 reueq1 ⊢ Base Scalar ⁡ C = B → ∃! g ∈ Base Scalar ⁡ C ∀ x ∈ V S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x ↔ ∃! g ∈ B ∀ x ∈ V S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x
17 15 16 syl ⊢ φ → ∃! g ∈ Base Scalar ⁡ C ∀ x ∈ V S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x ↔ ∃! g ∈ B ∀ x ∈ V S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x
18 14 17 mpbid ⊢ φ → ∃! g ∈ B ∀ x ∈ V S ⁡ F · ˙ x = g ∙ ˙ S ⁡ x